Price after off =80- 1/4 * 80 = 80-20 = $60
Coupon discount = 60*10/100 = $6
So, he have to pay, 60-6 = $54
After h hours A has 6000 - 2000h cells and B has 2000 - 1000h. Equating them as one form:
6000 - 2000h = 2000 - 1000h
-2000h + 1000h = 2000 - 6000
-1000h = -4000
h = -4000/-1000 = 4 hours
Going down the chart:
6
4
3
4
6
the brackets on the outside of the lxl makes the value positive or keeps the value positive. therefor if u have y=l-3l+3 y will still =6! hope this helps!
Please, use parentheses to enclose each fraction:
y=3/4X+5 should be written as <span>y=(3/4)X+5
Let's eliminate the fraction 3/4 by multiplying the above equation through by 4:
4[y] = 4[(3/4)x + 5]
Then 4y = 3x + 20
(no fraction here)
Let 's now solve the system
4y=3x + 20
4x-3y=-1
We are to solve this system using subtraction. To accomplish this, multiply the first equation by 3 and the second equation by 4. Here's what happens:
12y = 9x + 60 (first equation)
16x-12y = -4, or -12y = -4 - 16x (second equation)
Then we have
12y = 9x + 60
-12y =-16x - 4
If we add here, 12y-12y becomes zero and we then have 0 = -7x + 56.
Solving this for x: 7x = 56; x=8
We were given equations
</span><span>y=3/4X+5
4x-3y=-1
We can subst. x=8 into either of these eqn's to find y. Let's try the first one:
y = (3/4)(8)+5 = 6+5=11
Then x=8 and y=11.
You should check this result. Subst. x=8 and y=11 into the second given equation. Is this equation now true?</span>