Ever notice how there are practically no nines in pi? it's true. what's the longest continuous sequence not containing a nine in
the first million digits? (i want the sequence itself.)
1 answer:
Not sure if it is a school problem, but it is of interest to find the answer.
WithIn the first million digits of Pi, there are
5118-9 's
794-99 sequences
79-999 sequences
6-9999 sequences
2-99999 sequences
1-999999 sequence
Feel free to check the accuracy of above counts.
The 6-digit sequence starts at the 762th digit after the decimal point.
Digits of Pi including the first 800 digits after the decimal are included below:
3.14159265358979323846264338327950288419716939937510582097494459230781640628620899862803482534211706798214808651328230664709384460955058223172535940812848111745028410270193852110555964462294895493038196442881097566593344612847564823378678316527120190914564856692346034861045432664821339360726024914127372458700660631558817488152092096282925409171536436789259036001133053054882046652138414695194151160943305727036575959195309218611738193261179310511854807446237996274956735188575272489122793818301194912983367336244065664308602139494639522473719070217986094370277053921717629317675238467481846766940513200056812714526356082778577134275778960917363717872146844090122495343014654958537105079227968925892354201995611212902196086403441815981362977477130996051870721134999999837297804995105973173281609631859
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Answer:
20
Step-by-step explanation:
Answer:
Below
Step-by-step explanation:
● f(x) = -2x + 3
● f (0) = -2 (0) +3 = 3
● f(-32) = -2(-32)+3 = 64 + 3 = 67
● f(10) = -2(10) +3 = -20 + 3 = -17
● f(-17) = -2(-17) + 3 = 34 + 3 = 37
● f(10) => -17
● f(-17) => 37
Answer:
(10,27)
Step-by-step explanation:
Hope this helps!!! :)
Answer:
8 x 10/11 equals 69. If you mean something else, let me know.
Step-by-step explanation:
If you need any help, ask Brainly. Have a nice day!
