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Dominik [7]
2 years ago
10

Frank had 42 rocks that he wanted to share with his friends. If he gave each friend the same number of rocks(and kept the same n

umber of rocks for himself), how many rocks did each person get ?
Mathematics
1 answer:
shutvik [7]2 years ago
7 0

Answer:6. 42 split 7 ways is 6

Step-by-step explanation:

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Alexxandr [17]
The answer would be A if i am correct can i get most brainliest

6 0
3 years ago
Solve each system of equations.<br><br> 4x + 6y = 8<br> 5x – 4y = 25
Lubov Fominskaja [6]
\left \{ {{4x+6y=8} \atop {5x-4y=25}} \right. \\ \left \{ {{4x+6y=8} \atop {5x=25+4y}} \right.\\ \left \{ {{4x+6y=8} \atop {x=5+0.8y }} \right. \\ \left \{ {{4(5+0.8y)+6y=8} \atop {x=5+0.8y }} \right. \\  \left \{ {{20+3.2y+6y=8} \atop {x=5+0.8y }} \right. \\ \left \{ {{9.2y=-12} \atop {x=5+0.8y }} \right. \\ \left \{ {{y= -\frac{12}{9.2} } \atop {x=5+0.8y }} \right. \\  \left \{ {{y= -\frac{120}{92} } \atop {x=5+0.8(-\frac{12}{9.2}) }} \right. \\
\left \{ {{y= -1\frac{28}{92} } \atop {x=5-\frac{96}{92} }} \right. \\  \left \{ {{y= -1\frac{7}{23} } \atop {x=5-1\frac{1}{23} }} \right. \\   \left \{ {{y= -1\frac{7}{23} } \atop {x=4\frac{1}{23} }} \right. \\
\boxed{(x; y)=(4\frac{1}{23}; -1\frac{7}{23}) }





8 0
3 years ago
Why can two prime numbers only have one common factor?
Andreas93 [3]

A prime number has exactly two factors, 1 and itself. For example, 13 is a prime number because the only factors of 13 are 1 and 13. The number 8 is not prime because it has four factors: 1, 2, 4 and 8. The number 1 is not a prime number because it only has one factor (itself).

8 0
3 years ago
A factory requires 9 machines to make a toy
cestrela7 [59]

Answer:

18 machines

Step-by-step explanation:

9 machines give 24 mins... You need to reduce the time by half by adding using double the machines..

So 9×2=18

6 0
1 year ago
A Sample Of 100 Clients Of An Exercise Facility Was Selected. Let X- The Number Of Days Per Week That A Randomly Selected Client
julia-pushkina [17]

Answer: 1.013

Step-by-step explanation:

Given the following data :

X_______f___fx___fx²

1_______15__15___15

2______30__60__120

3______28__84__252

4______10__40___160

______ 83__199__547

Number that is 1.5 standard deviations below the mean :

Mean(m) :

Σfx /Σf

(15 + 30 + 28 + 10) / 83

= 199 / 83

= 2.3976

Standard deviation(s) :

Sqrt[(Σfx² - (Σfx)²/Σf) /Σf-1]

sqrt[(547 - (199)²/83) / 83 - 1]

sqrt[(547 - (39601/83) / 82]

sqrt[(547 - 477.12) / 82]

sqrt(0.8522)

Standard deviation = 0.9231

1.5 standard deviations below the mean:

Mean - 1.5(standard deviation)

2.3976 - 1.5(0.9231)

2.3976 -1.38465

= 1.01295

= 1.013

4 0
3 years ago
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