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Bumek [7]
2 years ago
8

-2z+3-z=□-4z+2 please give me the answer

Mathematics
2 answers:
eduard2 years ago
4 0
<h3>Answer: z=-1</h3>

Step-by-step explanation:

\displaystyle \rm -2z+3-z=-4z+2 \\\\ -3z+3=-4z+2 \\\\ 4z-3z=-3+2 \\\\ \underline{z=-1 \ \ \ \  } \\\\

vovikov84 [41]2 years ago
4 0

\large{\rm{\underline{\underline{Answer:}}}}

Given to solve: -2z+3-z = -4z+2

⇛ -3z + 3 = -4z + 2

⇛ -3z + 4z = 2 - 3

⇛ <u>z = -1</u>

Required value of z is -1. The steps we followed are: We shifted z to a single side and other numbers to other side. Then we equated to get the result.

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What would the set notation for the domain and range of the function, (-3, 6), (-2, -3), and (-1, 6)
Bingel [31]

Answer:

Domain: {-3, -2, -1}

Range: {-3, 6}

General Formulas and Concepts:

  • Domain is the set of x-values that can be inputted into function f(x).
  • Range is the set of y-values that are outputted by function f(x).

Step-by-step explanation:

<u>Step 1: Define</u>

(-3, 6)

(-2, -3)

(-1, 6)

<u>Step 2: Identify x-values</u>

x = -3, -2, -1

<u>Step 3: Identify y-values</u>

y = -3, 6, 6

7 0
3 years ago
There are 10 kids on the math team. Two kids will be selected from the team to compete in the state competition. How many ways a
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Answer:

45 ways

Step-by-step explanation:

Total number of kids = 10

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So the number ways to select two kids ^{10}C_2

We know that ^{n}C_r=\frac{n!}{r!(n-r)!}

So ^{10}C_2=\frac{10!}{2!(10-2)!}=\frac{10!}{2!\times 8!}=\frac{10\times 9\times 8!}{2\times 8!}=45

So there are 45 ways to select 2 competitors

8 0
3 years ago
3(x+2) = -5-2(x-3)<br><br> Please show your steps!!
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Step-by-step explanation:

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