What is the ratio of 1.6 million to 2.3 million

Which problem solving strategy would be best to solve this problem?Four people are in line at the movie theater. Jennifer is ahe

melamori03 [73]

Answer:

So it would be Jeanie in the back, John next, Jennifer, then Jarrett.

Step-by-step explanation:

Idk what you want me to answer on the A B C thing but that is the order they are in.

7 0

3 years ago

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How do you factor this polynomial as a product of more than two factors?<br> x3+8x2+15x

umka21 [38]

$x^3+8x^2+15x =\\
x(x^2+8x+15)=\\
x(x^2+3x+5x+15)=\\
x(x(x+3)+5(x+3))=\\
x(x+5)(x+3)
$

7 0

3 years ago

A coin toss is used to determine which team will receive the ball at the beginning of a football game. The Cougars always choose

Delvig [45]

Yes, depending on part of the wind flow maybe. But the Cougars would win atleast 2/3 games

3 0

3 years ago

I NEED help with this ASAP

boyakko [2]

Answer:

This triangle is a scalene triangle.

Step-by-step explanation:

A scalene triangle means that all of the sides are different.

Hope this helps!

3 0

3 years ago

Solve the given system of equations using either Gaussian or Gauss-Jordan elimination. (If there is no solution, enter NO SOLUTI

cricket20 [7]

Answer:

The system has infinitely many solutions

$\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}$

Step-by-step explanation:

Gauss–Jordan elimination is a method of solving a linear system of equations. This is done by transforming the system's augmented matrix into reduced row-echelon form by means of row operations.

An Augmented matrix, each row represents one equation in the system and each column represents a variable or the constant terms.

There are three elementary matrix row operations:

Switch any two rows
Multiply a row by a nonzero constant
Add one row to another

To solve the following system

$\begin{array}{ccccc}x_1&-3x_2&-2x_3&=&0\\-x_1&2x_2&x_3&=&0\\2x_1&+3x_2&+5x_3&=&0\end{array}$

Step 1: Transform the augmented matrix to the reduced row echelon form

$\left[ \begin{array}{cccc} 1 & -3 & -2 & 0 \\\\ -1 & 2 & 1 & 0 \\\\ 2 & 3 & 5 & 0 \end{array} \right]$

This matrix can be transformed by a sequence of elementary row operations

Row Operation 1: add 1 times the 1st row to the 2nd row

Row Operation 2: add -2 times the 1st row to the 3rd row

Row Operation 3: multiply the 2nd row by -1

Row Operation 4: add -9 times the 2nd row to the 3rd row

Row Operation 5: add 3 times the 2nd row to the 1st row

to the matrix

$\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]$

The reduced row echelon form of the augmented matrix is

$\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]$

which corresponds to the system

$\begin{array}{ccccc}x_1&&-x_3&=&0\\&x_2&+x_3&=&0\\&&0&=&0\end{array}$

The system has infinitely many solutions.

$\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}$

7 0

3 years ago