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Rom4ik [11]
3 years ago
10

AfcAAgrwdsgsFsefvzsdfvbjhbdjbbjbjsdndVHFadbhZJBVdb

Computers and Technology
2 answers:
lianna [129]3 years ago
8 0

Answer:AAAAAAFFFFFFTSSSSSSSSSGGGGGVVVVVVV

Explanation: YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET

ira [324]3 years ago
5 0
Hehdhfdhdhdhffhfhhfhddhfhhfdhehdyehdhd
You might be interested in
Glven an array named Scores with 25 elements, what is the correct way to assign the 25th element to myScore? A. myScores + 25 B.
Marat540 [252]

Answer:

myScore Scores[24]

Explanation:

The array is used to store the data in continuous memory location.

The index of array start from zero, it means first element store in the index zero and second element store in the index 1. So, the index at which the element store is less than 1 from the number of element.

so, the last element is 25 - 1=24.

Option A: myScores + 25

It is not the correct way to store the element.

Option B: myScore Scores[24]

it is the correct form and also the index location is correct.

Option C: myScore Scores[25)

index number is wrong and also the bracket is wrong, it must be [ ].

Option D: myScore== Score[last]

It is not the correct way to store the element.

There, the correct option is B.

6 0
3 years ago
A circuit has a resistance of 300 ohm and a current of 0.024 A. What is the voltage in the circuit?
fomenos
**Formula

If u want to calculate voltage:
Current x Resistance

so the answer is D

Current:
Voltage ÷ Resistance

Resistance:
Voltage ÷ Current
7 0
3 years ago
When you block a number can they still text??
noname [10]
When a blocked number tries to send you a text message, it won’t go through, and they will likely never see the “delivered” note. On your end, you’ll see nothing at all. As far as phone calls are concerned, a blocked call goes directly to voice mail. On your end, you’ll get a special “blocked messages” folder in your voice mail inbox if they leave a message, but you won’t get a notification they called.
5 0
3 years ago
Given an array as follows
slava [35]

Answer:

1) Method calcTotal:

  1. public static long calcTotal(long [][] arr2D){
  2.        long total = 0;
  3.        
  4.        for(int i = 0; i < arr2D.length; i++ )
  5.        {
  6.            for(int j = 0; j < arr2D[i].length; j++)
  7.            {
  8.                total = total + arr2D[i][j];
  9.            }
  10.        }
  11.        
  12.        return total;
  13.    }

Explanation:

Line 1: Define a public method <em>calcTotal</em> and this method accept a two-dimensional array

Line 2: Declare a variable, total, and initialize it with zero.

Line 4: An outer for-loop to iterate through every rows of the two-dimensional array

Line 6: An inner  for-loop to iterate though every columns within a particular row.

Line 8: Within the inner for-loop, use current row and column index, i and j, to repeatedly extract the value of each element in the array and add it to the variable total.

Line 12: Return the final total of all the element values as an output

Answer:

2) Method calcAverage:

  1. public static double calcAverage(long [][] arr2D){
  2.        double total = 0;
  3.        int count = 0;
  4.        
  5.        for(int i = 0; i < arr2D.length; i++ )
  6.        {
  7.            for(int j = 0; j < arr2D[i].length; j++)
  8.            {
  9.                total = total + arr2D[i][j];
  10.                count++;
  11.            }
  12.            
  13.        }
  14.        
  15.        double average = total / count;
  16.        
  17.        return average;
  18.    }

Explanation:

The code in method <em>calcAverage</em> is quite similar to method <em>calcTotal</em>. We just need to add a counter and use that counter as a divisor of total values to obtain an average.

Line 4: Declare a variable, count, as an counter and initialize it to zero.

Line 11: Whenever an element of the 2D array is added to the total, the count is incremented by one. By doing so, we can get the total number of elements that exist in the array.

Line 16: Use the count as a divisor to the total to get average

Line 18: Return the average of all the values in the array as an output.

Answer:

3) calcRowAverage:

  1. public static double calcRowAverage(long [][] arr2D, int row){
  2.        double total = 0;
  3.        int count = 0;
  4.        
  5.        for(int i = 0; i < arr2D.length; i++ )
  6.        {
  7.            if(i == row)
  8.            {
  9.                for(int j = 0; j < arr2D[i].length; j++)
  10.                {
  11.                    total = total + arr2D[i][j];
  12.                    count++;
  13.                }
  14.            }
  15.            
  16.        }
  17.        
  18.        double average = total / count;
  19.        
  20.        return average;
  21.    }

Explanation:

By using method <em>calcAverage </em>as a foundation, add one more parameter, row, in the method <em>calcRowAverage</em>. The row number is used as an conditional checking criteria to ensure only that particular row of elements will be summed up and divided by the counter to get an average of that row.

Line 1: Add one more parameter, row,

Line 8-15: Check if current row index, i, is equal to the target row number, proceed to sum up the array element in that particular row and increment the counter.

5 0
3 years ago
Using tracking code, Google Analytics can report on data from which systems? (select all answers that apply)
Jobisdone [24]

Answer:

a b c

Explanation:

they can report data from these three options

6 0
3 years ago
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