Answer:
numbers = 1:1:100;
for num=numbers
remainder3 = rem(num,3);
remainder5 = rem(num,5);
if remainder3==0
disp("Yee")
else
if remainder3 == 0 && remainder5 == 0
disp ("Yee-Haw")
else
if remainder5==0
disp("Haw")
else
disp("Not a multiple of 5 or 4")
end
end
end
end
Explanation:
- Initialize the numbers variable from 1 to 100.
- Loop through the all the numbers and find their remainders.
- Check if a number is multiple of 5, 3 or both and display the message accordingly.
Answer:
Following are the code to the given question:
#include <iostream>//header file
using namespace std;
class Window //defining a class Window
{
private:
int width, height;//defining integer variable
public:
friend ostream& operator << (ostream& stm, Window& width)//defining a friend function that takes two parameters
{
return stm<<"a ("<<width.width<<" x "<<width.height<<") window"; //use return keyword that return its values
}
Window(int width, int height): width(width), height(height)//defining parameterized constructor that inherit width and height in its parameters
{}
};
int main() //Main method
{
Window w(80,90);//calling class constructor
cout<<w;//print object value
return 0;
}
Output:
a (80 x 90) window
Explanation:
In the above code, a class "Window" is defined that uses a friend function "ostream& operator" is declared that uses the "ostrea&" as a data type to hold two-variable "stm and w" in its parameter, and declared the parameterized constructor to hold value by inheriting width and height in its parameters.
Inside the main method, a class object is created that calls the constructor and uses the print method to print object value.
Answer:
Data mining is a process of extracting and discovering patterns in large data sets involving methods at the intersection of machine learning, statistics, and database systems.
