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AleksAgata [21]
2 years ago
13

What year was internet inverted

Computers and Technology
1 answer:
alex41 [277]2 years ago
5 0

\large\blue{\mid{\underline{\overline{\tt { →\:January \:1, 1983}\mid}}}}

  • ARPANET→Advanced Research Projects Agency Network
  • the forerunner of the Internet.

\purple{\rule{15mm}{2.9pt}} \red{\rule18mm{2.5pt}} \orange{ \rule18mm{2.5pt}}

\sf{\:мѕнαcкεя\: ♪...}

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What value(s) can be input into this code for the value of number that will cause the code in the loop to execute? Scanner keybo
Marianna [84]

Answer:

There is no value of the number variable, for which the loop can be true in any iteration.

Explanation:

  • The above loop states the condition that the value should be less than 100 and greater than 500. It is because the loop holds the and condition which gives the true if both conditions will be true.
  • The first condition of the while loop states that the value of the number variable is less than the 100.
  • The second condition of the while loop state that the value of the number variable is greater than the 500.
  • The and condition of the while loop will true if both conditions will true.
  • But there is no number which is less than 100 and greater than 500.
  • So no number can satisfy the while condition to be true.

5 0
3 years ago
“Click” is a type of user input the onEvent code checks for in order to perform actions like going to another screen. List at le
Sidana [21]

Answer:

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5 0
3 years ago
Complete this truth Table. Write a program that you can enter from the keyboard, a 1 or 0 into three Boolean variables, A,B,C. W
SSSSS [86.1K]

Answer:

Following are the code to this question:

#include<stdio.h>//defining header file

int AND(int x,int y) //defining a method AND that hold two variable in its parameter

{

if(x==1 && y==1)//defining if block to check x and y value is equal to 1

{

return 1;//return value 1

}

else //defining else block

{

   return 0;//return value 0

}

}

int OR(int x,int y)//defining method OR that hold two variable in its parameter

{

if(x==0&&y==0)//defining if block to check x and y value is equal to 1

{

return 0;//return value 0

}

else //defining else block

{

   return 1;//return value 1

}

}

int main()//defining main method

{

int a,b,c;//defining integer variable  

int k=1;//defining integer variable k that holds a value 1

while(k<=8)//defining while loop for 8 time input

{

printf("Please insert 3 numbers in (0 0r 1):\n ");//print message

scanf("%d%d%d", &a, &b, &c);//input value

k++;//increment the value of k by 1

printf("value: %d\n",AND(OR(a,b),c));

}

return 0;

}

Output:

please find the attachment.

Explanation:

In the above-given C language code two methods "AND and OR" is declared, holds two integer variable "x and y" in its parameters, inside the method a conditional it used that can be defined as follows:

  • In the AND method, inside a conditional statement, if block check x and y both value is same that is 1 it will return 1 or it will goto else block in this it will return value 0.      
  • In the OR method, inside a conditional statement, if block check x and y both value is the same, that is 0 it will return 0 or it will goto else block in this it will return value 1.
  • In the main method, four integers "a,b,c, and k" is declared in which variable "a, b, c" is used in the loop for 8 times input values from the user and print method is used to call the method and prints its return values.

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3 years ago
Choose the correct comparison statement about delivery and read receipts.
Lostsunrise [7]

Answer:

A: Delivery receipts can be enabled for all messages, while read receipts can be turned off by the recipient.

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3 years ago
Which company introduce the first Minicomputer in 1960.​
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Answer:

<em>t</em><em>h</em><em>e</em><em> </em><em>f</em><em>i</em><em>r</em><em>s</em><em>t</em><em> </em><em>m</em><em>i</em><em>n</em><em>i</em><em>c</em><em>o</em><em>m</em><em>p</em><em>u</em><em>t</em><em>e</em><em>r</em><em> </em><em>w</em><em>a</em><em>s</em><em> </em><em>i</em><em>n</em><em>t</em><em>r</em><em>o</em><em>d</em><em>u</em><em>c</em><em>e</em><em> </em><em>b</em><em>y</em><em> </em><em>d</em><em>i</em><em>g</em><em>i</em><em>t</em><em>a</em><em>l</em><em> </em><em>e</em><em>q</em><em>u</em><em>i</em><em>p</em><em>m</em><em>e</em><em>n</em><em>t</em><em> </em><em>c</em><em>o</em><em>r</em><em>o</em><em>p</em><em>o</em><em>r</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>D</em><em>E</em><em>C</em><em>)</em><em>a</em><em>f</em><em>t</em><em>e</em><em>r</em><em> </em><em>t</em><em>h</em><em>e</em><em>s</em><em>e</em><em> </em><em>I</em><em>B</em><em>M</em><em> </em><em>c</em><em>o</em><em>r</em><em>p</em><em>o</em><em>r</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>a</em><em>l</em><em>s</em><em>o</em><em> </em><em>m</em><em>i</em><em>n</em><em>i</em><em>c</em><em>o</em><em>m</em><em>p</em><em>u</em><em>t</em><em>e</em><em>r</em><em> </em><em>f</em><em>o</em><em>r</em><em> </em><em>e</em><em>x</em><em>a</em><em>m</em><em>p</em><em>l</em><em>e</em><em> </em><em>P</em><em>D</em><em>P</em><em>–</em><em>1</em><em>1</em>

7 0
3 years ago
Read 2 more answers
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