You have an upcoming exam and you are confident that you have read all your books and believe you know your stuff down cold. Somehow, after sitting for your exam, you fail. To avoid this from happening again, you can use methods like SQRW or KWL to make sure that you get a better grade. Each of these techniques are initials that stand for “Survey”, “Question”, “Read”, and “Write” (SQRW) and “Know,” “Want to Know,” and “Learned” (KWL) respectively. People who make the most out of these two strategies will understand what they read and prepare notes of what they learned. These notes will come in handy when sitting for an exam. KWL, specifically, help student become better versions of themselves and improve in reading expository text.
Answer:Tekken 3 features a largely new cast of characters, including the debut of several now-staple characters such as Jin Kazama, Ling Xiaoyu, Bryan Fury, Eddy Gordo and Hwoarang, with a total of twenty-three characters.
Explanation: I feel like the answer is pretty strait forward.
Good is for aware consumers who value quality of life, fashion, and the environment. The areas of home, fashion, gardening, crafts, travel, health, and beauty are all covered in each issue of Good.
<h3>What journal entry to record the sales not yet earned?</h3>
When a business sells any merchandise to a third party on credit, an entry called a sales credit journal entry is made in the company's sales journal.
There is usually a selection of delectable dishes as well as professional advice on relationships, wellness, and nutrition.
Therefore, In this instance, the sales account is credited in proportion to the debit to the debtor's account or account receivable account.
Learn more about journal entry here:
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Answer:
Merge sort is a sorting technique based on divide and conquer technique.
Explanation:
MERGE(A, p, q, r)
n1 = q - p + 1
n2 = r - q
L[1..n1] and R[1..n2] this creates the new array
for i = 1 to n1
L[i] = A[p + i - 1]
for j = 1 to n2
R[j] = A[q + j]
i = 1
j = 1
for k = p to r
if i > n1
A[k] = R[j]
j = j + 1
else if j > n2
A[k] = L[i]
i = i + 1
else if L[i] ≤ R[j]
A[k] = L[i]
i = i + 1
else
A[k] = R[j]
j = j + 1
