Simplify the following:(9 y)^2/(3 (3 y)^2 y^4)
Multiply each exponent in 3 y by 2:(9 y)^2/(3×3^2 y^2 y^4)
3^2 = 9:(9 y)^2/(3×9 y^2 y^4)
Multiply each exponent in 9 y by 2:(9^2 y^2)/(3×9 y^2 y^4)
9^2 = 81:(81 y^2)/(3×9 y^2 y^4)
(81 y^2)/(3×9 y^2 y^4) = y^2/y^2×81/(3×9 y^4) = 81/(3×9 y^4):81/(3×9 y^4)
3 | 2 | 7 | 8 | 1- | 6 | | 2 | 1- | 2 | 1 | | 0:27/(9 y^4)
27/9 = (9×3)/9 = 3:Answer: 3/y^4
Answer:
Option B) 3.04
Step-by-step explanation:
We are given the following in the question:
Number of people interviewed,n = 163
Number of people hire, x = 121
Proportion of people hire =
![\dfrac{x}{n} = \dfrac{121}{163} = 0.742](https://tex.z-dn.net/?f=%5Cdfrac%7Bx%7D%7Bn%7D%20%3D%20%5Cdfrac%7B121%7D%7B163%7D%20%3D%200.742)
Mean, μ = 3.3
Standard Deviation, σ = 0.4
We are given that the distribution of GPA for the successful interviewees is a bell shaped distribution that is a normal distribution.
Formula:
![z_{score} = \displaystyle\frac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=z_%7Bscore%7D%20%3D%20%5Cdisplaystyle%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
We have to find the value of x such that the probability is 0.742
Calculation the value from standard normal z table, we have,
Thus, cut-off GPA should be 3.04.
Option B) 3.04
36 months = 3 years
34,100*(1.04)^3 = $38357.86
Answer:
B. 50 students in her school
Step-by-step explanation:
Every other answer is at a seperate place designed to help someone in a specific field, besides the school.
The answer is 90 people because total amount of people is 300