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Kisachek [45]
2 years ago
6

If i can get 2 prego pasta sauce for $8 how much would it be for 1 prego pasta?

Mathematics
2 answers:
Sphinxa [80]2 years ago
3 0

Answer: $4

Step-by-step explanation:

If you have 2 Prego pasta sauces at $8 and you only want half of that (1), you divide 8 by 2 to get 4. 1 pasta sauce equals $4

Elanso [62]2 years ago
3 0

Answer:

$4

Step-by-step explanation:

divide 8 by two

to find the price of one prego pasta divide the cost of your object  by the amount of objects

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The round wading pool at the Greenville Community Center has a diameter of 8 feet. What is the pool's circumference? use 3.14 fo
HACTEHA [7]

The circumference of pool is 25.12 feet

<em><u>Solution:</u></em>

Given that round wading pool at the Greenville Community Center has a diameter of 8 feet

Therefore,

Diameter = 8 feet

We know that,

Radius = \frac{diameter}{2}\\\\Radius = \frac{8}{2}\\\\Radius = 4

Thus radius is 4 feet

<em><u>The circumference of circle is given by formula:</u></em>

C = 2 \pi r

Where, "r" is the radius of circle

Substitute r = 4

C = 2 \times 3.14 \times 4\\\\C = 25.12

Thus circumference of pool is 25.12 feet

7 0
3 years ago
Doy 35 puntos al que me responda esto bien pero una persona que sepa plissss ​
Tatiana [17]

7,8 y 10 adios amigo esa es la respuesta que necesitas

3 0
2 years ago
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Use variation of parameters to find a general solution to the differential equation given that the functions y1 and y2 are linea
Aleks [24]

Recall that variation of parameters is used to solve second-order ODEs of the form

<em>y''(t)</em> + <em>p(t)</em> <em>y'(t)</em> + <em>q(t)</em> <em>y(t)</em> = <em>f(t)</em>

so the first thing you need to do is divide both sides of your equation by <em>t</em> :

<em>y''</em> + (2<em>t</em> - 1)/<em>t</em> <em>y'</em> - 2/<em>t</em> <em>y</em> = 7<em>t</em>

<em />

You're looking for a solution of the form

y=y_1u_1+y_2u_2

where

u_1(t)=\displaystyle-\int\frac{y_2(t)f(t)}{W(y_1,y_2)}\,\mathrm dt

u_2(t)=\displaystyle\int\frac{y_1(t)f(t)}{W(y_1,y_2)}\,\mathrm dt

and <em>W</em> denotes the Wronskian determinant.

Compute the Wronskian:

W(y_1,y_2) = W\left(2t-1,e^{-2t}\right) = \begin{vmatrix}2t-1&e^{-2t}\\2&-2e^{-2t}\end{vmatrix} = -4te^{-2t}

Then

u_1=\displaystyle-\int\frac{7te^{-2t}}{-4te^{-2t}}\,\mathrm dt=\frac74\int\mathrm dt = \frac74t

u_2=\displaystyle\int\frac{7t(2t-1)}{-4te^{-2t}}\,\mathrm dt=-\frac74\int(2t-1)e^{2t}\,\mathrm dt=-\frac74(t-1)e^{2t}

The general solution to the ODE is

y = C_1(2t-1) + C_2e^{-2t} + \dfrac74t(2t-1) - \dfrac74(t-1)e^{2t}e^{-2t}

which simplifies somewhat to

\boxed{y = C_1(2t-1) + C_2e^{-2t} + \dfrac74(2t^2-2t+1)}

4 0
3 years ago
Oprs]
abruzzese [7]

Answer:

Soccer = 120

Tennis = 220

Step-by-step explanation:

The total number of students enrolling for soccer and tennis classes is, 340.

The ratio number of students enrolling for soccer and tennis classes is, 6:11.

Then,

6x + 11x = 340

17x = 340

x = 20

The number of students enrolled for soccer class is, 6x = 6 × 20 = 120.

The number of students enrolled for tennis class is, 11x = 11 × 20 = 120.

8 0
3 years ago
What is the rounding or compatible sum of 18+53
Semenov [28]
71 is the answer. If you round it, it would be 70.
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