The circumference of pool is 25.12 feet
<em><u>Solution:</u></em>
Given that round wading pool at the Greenville Community Center has a diameter of 8 feet
Therefore,
Diameter = 8 feet
We know that,

Thus radius is 4 feet
<em><u>The circumference of circle is given by formula:</u></em>

Where, "r" is the radius of circle
Substitute r = 4

Thus circumference of pool is 25.12 feet
7,8 y 10 adios amigo esa es la respuesta que necesitas
Recall that variation of parameters is used to solve second-order ODEs of the form
<em>y''(t)</em> + <em>p(t)</em> <em>y'(t)</em> + <em>q(t)</em> <em>y(t)</em> = <em>f(t)</em>
so the first thing you need to do is divide both sides of your equation by <em>t</em> :
<em>y''</em> + (2<em>t</em> - 1)/<em>t</em> <em>y'</em> - 2/<em>t</em> <em>y</em> = 7<em>t</em>
<em />
You're looking for a solution of the form

where


and <em>W</em> denotes the Wronskian determinant.
Compute the Wronskian:

Then


The general solution to the ODE is

which simplifies somewhat to

Answer:
Soccer = 120
Tennis = 220
Step-by-step explanation:
The total number of students enrolling for soccer and tennis classes is, 340.
The ratio number of students enrolling for soccer and tennis classes is, 6:11.
Then,
6x + 11x = 340
17x = 340
x = 20
The number of students enrolled for soccer class is, 6x = 6 × 20 = 120.
The number of students enrolled for tennis class is, 11x = 11 × 20 = 120.
71 is the answer. If you round it, it would be 70.