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4 years ago

Round 43.586 to nearest tenth

Mathematics

2 answers:

ruslelena [56]4 years ago

5 0

The answer is 43.6 for the question

MArishka [77]4 years ago

5 0

43.6 because 8 is greater than 4 so you round up

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F(x) = x^2 + 4x + 20 find the real roots. take your time if you want :)

s344n2d4d5 [400]

Answer:

No real roots

$x = -2 + 4i, x = -2 - 4i$

Step-by-step explanation:

Hello!

We can solve the quadratic by using the Quadratic Formula.

Standard form of a Quadratic: $ax^2 + bx + c = 0$

Quadratic Equation: $x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}$

Given our Equation: $f(x) = x^2 + 4x + 20$

a = 1
b = 4
c = 20

Set the equation to 0 and solve using the formula.

<h3>Solve</h3>

$x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}$
$x = \frac{-4\pm\sqrt{4^2 - 4(1)(20)}}{2(1)}$
$x = \frac{-4\pm\sqrt{16 - 80}}{2}$
$x = \frac{-4\pm\sqrt{-64}}{2}$
$x = \frac{-4\pm8i}{2}$
$x = -2 + 4i, x = -2 - 4i$

There are no real roots to the quadratic.

8 0

2 years ago

assuming the pick-up trucks trailers and road conditions are exactly the same which vehicle will take a longer distance to stop

NemiM [27]

I’ve answered this before so I know the question is missing an

important given and that given is: 1 has an

empty trailer and the other has a fully loaded one.

So, it would be the fully loaded trailer that would take a longer distance to

stop because a lot of weight is being pulled, and when the brakes are started,

the fully loaded trailer is more like pushing against the truck.

3 0

4 years ago

How far will a cyclist travel in 1/4 hour if he cycles at 18 kilometres per hour

Zinaida [17]

In one hour he would cycle 18Km, therefore in a 1/4 hour the cyclist would ride a 1/4 of 18 = 4.5Km.

3 0

3 years ago

3(x + 6) = 72<br><br> Please help. I think it's either<br><br> 30 or 18

Amanda [17]

The correct answer is 18 . if you follow pemdas it really helps.

3 0

3 years ago

Parallelogram MNPQ has vertices at M(5,14), N(10,16), P(12,11), Q(7,9). Just using the Diagonals,

Julli [10]

Answer:

square

Step-by-step explanation:

You use the Pitagora's theorem to calculate the diagonals of the figure.

The diagonals are given by the distance NQ and MP.

By calculating the value of these diagonals you have:

$d_{NQ}=\sqrt{(10-7)^2+(16-9)^2}=\sqrt{58}\\\\d_{MP}=\sqrt{(12-5)^2+(11-14)^2}=\sqrt{58}$

These diagonlas are equal between them. Hence, the figure is a square

6 0

4 years ago