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jeka57 [31]
3 years ago
12

Please help!? 5 Stars! :0 :(

Mathematics
1 answer:
zvonat [6]3 years ago
6 0

OK.  These problems are easy if you know the quadratic formula,
and they're impossible if you don't.

Here's the quadratic formula:

When the equation is in the form of      Ax² + Bx + C = 0

then                    x =  [ -B plus or minus √(B²-4AC) ] / 2A

I'm sure that formula is in your text or your study notes,
right before these questions.  You should cut it out or
copy it, and tape it inside the cover of your notebook.
Then, you'll always have it when you need it, until
you have it memorized and can rattle it off.

The first question says        3x²  +  5x  +  2  = 0

Is this in the form of             Ax²  +  Bx  +  C  = 0    ?

             Yes !                    A=3      B=5   C=2

             so you can use the quadratic formula to solve it.

            x =  [ -B plus or minus √(B²-4AC) ] / 2A

               =  [ -5 plus or minus √(5² - 4·3·2) ] / 2·3

               =  [ -5 plus or minus √(25 - 24)  ]  /  6

               =  [  -5 plus or minus  √1          ]  /  6

           x  =        -4 / 6  =  -2/3
and
           x  =        -6 / 6  =  -1 .    
_______________________________________

The second question says

                                         4x²  +  5x  -  1 = 0

Is this in the form of          Ax²  +  Bx + C = 0  ?

           Yes it is !            A=4     B=5   C= -1  

         so you can use the quadratic formula to solve it.

            x =  [ -B plus or minus √(B²-4AC) ] / 2A

Now, you take it from here.

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Afina-wow [57]
I think it's A! definitely not C or D
8 0
2 years ago
A train left a station at 8:13 a.m. arriving at its destination at 4:52 p.m. If the stations are 527.65 miles apart, calculate t
Tomtit [17]

9514 1404 393

Answer:

  D.  61 mi/h

Step-by-step explanation:

The travel time is 16:52 -8:13 = 8:39 hours, or 8.65 hours. Then the speed is ...

 speed = distance/time = 527.65 mi/(8.65 h) = 61 mi/h

_____

<em>Additional comment</em>

It is often convenient to use "military" or "24-hour" time for calculations of time periods that extend over noon or midnight. For this purpose, 12 gets added to the hour number in the afternoon (pm). Of course, 39 minutes is 39/60 hours. That is found to be 0.65 hours by performing the division of 39 by 60.

6 0
2 years ago
Use function notation to represent the average speed of the car on the interval from t = 2 to t = 7 .
Afina-wow [57]

Answer:

Average\ Speed = \frac{s(7) - s(2)}{5}

Step-by-step explanation:

Given

t = 2 to 7

Required

Find the average speed over these intervals

The function is not given; so, I'll represent the function as s(t)

When t = 2;

s(t)= s(2)

When t = 7

s(t) = s(7)

Average\ Speed = \frac{Change\ in\ Distance}{Change\ in\ Time}

This gives:

Average\ Speed = \frac{s(7) - s(2)}{7 - 2}

Average\ Speed = \frac{s(7) - s(2)}{5}

5 0
3 years ago
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Jobisdone [24]

Answer:

the answer would be 13

Step-by-step explanation:

26/2=13

3 0
3 years ago
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kolezko [41]

Answer:

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