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padilas [110]
4 years ago
14

20 points please hurry

Mathematics
2 answers:
Brrunno [24]4 years ago
6 0

Answer:

Step-by-step explanation:

y = (x - 2)(x + 3) has roots at x = 2 and x = -3.  Only the fourth answer choice shows this fact.

VLD [36.1K]4 years ago
4 0

Answer:

C

Step-by-step explanation:

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Compute the directional derivative of the following function at the given point P in the direction of the given vector. Be sure
borishaifa [10]

Answer:

The directional derivate is given by: D_{u}(x,y) = \frac{6}{\ln{17}\sqrt{10}}

Step-by-step explanation:

The directional derivative at point (x,y) is given by:

D_{u}(x,y) = f_{x}(x,y)*a + f_{y}(x,y)*b

In which a is the x component of the unit vector and b is the y component of the unit vector.

Vector:

We are given the following vector: v = (3,1)

Its modulus is given by: \sqrt{3^2 + 1^2} = \sqrt{10}

The unit vector is given by each component divided by it's modulus. So

v_u = (\frac{3}{\sqrt{10}}, \frac{1}{\sqrt{10}})

This means that a = \frac{3}{\sqrt{10}}, b = \frac{1}{\sqrt{10}}

Partial derivatives:

f(x,y) = \ln{(2 + 3x^2 + 3y^2)}

So

f_x(x,y) = \frac{6x}{\ln{(2 + 3x^2 + 3y^2)}}

f_x(1,-2) = \frac{6(1)}{\ln{(2 + 3(1)^2 + 3(-2)^2)}} = \frac{6}{\ln{17}}

f_y(x,y) = \frac{6y}{\ln{(2 + 3x^2 + 3y^2)}}

f_y(1,-2) = \frac{6(-2)}{\ln{(2 + 3(1)^2 + 3(-2)^2)}} = -\frac{12}{\ln{17}}

Directional derivative:

D_{u}(x,y) = f_{x}(x,y)*a + f_{y}(x,y)*b

D_{u}(x,y) = \frac{6}{\ln{17}}\times\frac{3}{\sqrt{10}}-\frac{12}{\ln{17}}\times\frac{1}{\sqrt{10}}

D_{u}(x,y) = \frac{18}{\ln{17}\sqrt{10}} - \frac{12}{\ln{17}\sqrt{10}}[tex][tex]D_{u}(x,y) = \frac{6}{\ln{17}\sqrt{10}}

The directional derivate is given by: D_{u}(x,y) = \frac{6}{\ln{17}\sqrt{10}}

8 0
3 years ago
Which statement describes the inverse of m(x) = x2 – 17x?
stealth61 [152]

Answer:

The correct option is;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

Step-by-step explanation:

The given information is that m(x) = x² - 17·x

The above equation can be written in the form;

y = x² - 17·x

Therefore;

0 = x² - 17·x - y

From the general solution of a quadratic equation, 0 = a·x² + b·x + c we have;

x = \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}

By comparison to the equation,0 = x² - 17·x - y, we have;

a = 1, b = -17, and c = -y

Substituting the values of a, b and c into the formula for the general solution of a quadratic equation, we have;

x = \dfrac{-(-17)\pm \sqrt{(-17)^{2}-4\times (1) \times (-y)}}{2\times (1)} = \dfrac{17\pm \sqrt{289+4\cdot y}}{2}

Which can be simplified as follows;

x =  \dfrac{17\pm \sqrt{289+4\cdot y}}{2}= \dfrac{17}{2} \pm \dfrac{1}{2}  \times \sqrt{289+4\cdot y}} = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +\dfrac{4\cdot y}{4} }}

And further simplified as follows;

x = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +y }} = \dfrac{17}{2} \pm \sqrt{y + \dfrac{289}{4} }}

Interchanging x and y in the function of the inverse, m⁻¹(x), we have;

m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

We note that the maximum or minimum point of the function, m(x) = x² - 17·x found by differentiating the function and equating the result to zero, gives;

m'(x) = 2·x - 17 = 0

x = 17/2

Similarly, the second derivative is taken to determine if the given point is a maximum or minimum point as follows;

m''(x) = 2 > 0, therefore, the point is a minimum point on the graph

Therefore, as x increases past the minimum point of 17/2, m⁻¹(x) increases to give;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }} to increase m⁻¹(x) above the minimum.

8 0
3 years ago
Does the choice of the base affect the perimeter of a triangle?
forsale [732]
No. 
The perimeter is the distance all the way around the triangle. 
So it's the sum of the lengths of the three sides. 

The sum of three numbers doesn't depend on what order you
add them ... I think that's the 'commutative' property of addition. 

So it doesn't matter which side you start with, or even what order
the sides are arranged in.  The perimeter is always the same.
7 0
3 years ago
Hey:) can you please help me posted picture of question
AnnZ [28]
Answer:
x⁴ + 6x² + 9

Explanation:
To answer this question, we will multiply each term from the first bracket by each term from the second bracket and then combine like terms to get the final expression.

This can be done as follows:
(x² + 3)(x² + 3)
x²(x²) + x²(3) + 3(x²) + 3(3)
x⁴ + 3x² + 3x² + 9
x⁴ + 6x² + 9

Hope this helps :)
5 0
3 years ago
Read 2 more answers
Need help on this please
Alex787 [66]
3 is the first one.
-1 is the 2nd
and 7 is the 3rd
3 0
4 years ago
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