They could have travelled any distance. In total, they travelled 1.75 times the distance of the first day, but since we do not know the distance of the first day, we have no idea the actual distance. For all we know they could have gone to the moon in the first day.
I don't have a calculator near me... but you probably do. So just plug in those values for t.
Y = 4(-3) ^2 + 5
(Actually.. I might be able to do these in my head...) Y = 41
Y = 4(-1.5) ^2 + 5
Y = 14
Y = 4(0) ^2 + 5
Y = 5
Y = 4(1) ^2 + 5
Y = 9
Y = 4(4) ^2 + 5
Y = 69
The range is all the Y values. So it would be {41, 14, 5, 9, 69}
Answer:
6
Step-by-step explanation:
70/84 = 5/N
70N = 420
N = 420/70 = 6
Given:
The equation is:
To find:
The solution for the given equation.
Solution:
We have,
It can be written as:
![[\because \ln e^x=x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Cln%20e%5Ex%3Dx%5D)
![[\because \ln a+\ln b=\ln (ab)]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Cln%20a%2B%5Cln%20b%3D%5Cln%20%28ab%29%5D)
![[\because \ln x^n=n\ln x ]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Cln%20x%5En%3Dn%5Cln%20x%20%5D)
On comparing both sides, we get
Taking cube root, we get
![x=\sqrt[3]{64}](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B3%5D%7B64%7D)
Therefore, the required solution is .
