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Sergio039 [100]
3 years ago
8

Help I have a C in math. I don't understand this Alegbra. If you get it right then I will give you Brainlist!​

Mathematics
1 answer:
Kruka [31]3 years ago
3 0

Answer:

we're going to need a picture </3

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Chia is planning a sailing party for her friends the boat rental is $150 plus an additional $15 per person see it has saved up $
storchak [24]
150 + 15x = 400
(-150) 150 + 15x = 400 (-150)
15x = 250
(/15) 15x = 250 (/15)
x = 16.67
So Chia can invite 16 people
3 0
3 years ago
Read 2 more answers
Solve the following inequality.
Anika [276]

Solving the inequality given algebraically, the solution of the inequality for the value of m is:

<u>m < -4 OR m > 3</u>

<em><u>Given the following </u></em><em><u>inequality</u></em><em><u>,</u></em>

<em><u /></em>\frac{m - 2}{3} < -2 \\

or

4m + 3 > 15

Let's solve algebraically for the value of m in both inequality statements given.

\frac{m - 2}{3} < -2 \\

  • Multiply both sides by 3

\frac{m - 2}{3} \times 3 < -2 \times 3\\\\m - 2 < -6

  • Add 2 to both sides

m - 2 + 2 < -6 + 2\\\\m < -4

Or

4m + 3 > 15

  • Subtract 3 from each side

4m + 3 - 3 > 15 - 3

4m > 12

  • Divide both sides by 4

\frac{4m}{4}  > \frac{12}{4} \\\\

m > 3

Therefore, solving the inequality given algebraically, the solution of the inequality for the value of m is:

<u>m < -4 OR m > 3</u>

<u></u>

<u></u>

Learn more here:

brainly.com/question/24434501

8 0
2 years ago
HELP PLS Last year 15 students earned an A in math class. If I had 128 students, what percent of students did NOT earn an A?
BabaBlast [244]

Answer:

88%

Step-by-step explanation:

128-15=113

113/128=.882

88%

8 0
2 years ago
Help me please I got to finish it
Scorpion4ik [409]

Answer:

\frac{52}{63}

4 0
3 years ago
Solve the decay equation y' = -ky using the integrating factors method. Show work
Alex777 [14]

Answer:

y=\frac{c}{e^{kx}}

Step-by-step explanation:

\frac{\mathrm{d} y}{\mathrm{d} x} =-ky

\frac{\mathrm{d} y}{\mathrm{d} x} +ky=0

comparing with equation

\frac{\mathrm{d} y}{\mathrm{d} x} + Py=Q(x)

I.F.= e^{\int P dx}

I.F.= e^{\int k dx}

I.F.= e^{kx}

y=\frac{1}{I.F.} ( \int {Q(x)}  dx  +c)

y=\frac{1}{e^{kx}} ( \int {0}  dx  +c)

y=\frac{c}{e^{kx}}

7 0
3 years ago
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