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2 years ago

HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME

Mathematics

1 answer:

TiliK225 [7]2 years ago

5 0

Answer:

Step-by-step explanation:

First, you want to do inverse operations like I said on the last equation

Just divide -4 with 64

You have to flip the inequality sign because you divided by a negative

Answer: g ≥ -16

Now what is greater than or equal to -16?

Answer =

-16

-11

-6

-13

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Use the Fundamental Theorem of Calculus to find the area of the region between the graph of the function x5 + 8x4 + 2x2 + 5x + 1

belka [17]

Answer:

The area of the region between the graph of the given function and the x-axis = 25,351 units²

Step-by-step explanation:

Given x⁵ + 8 x⁴ + 2 x² + 5 x + 15

If 'f' is a continuous on [a ,b] then the function

$F(x) = \int\limits^a_b {f(x)} \, dx$

By using integration formula

$\int{x^n} \, dx = \frac{x^{n+1} }{n+1} +c$

Given x⁵ + 8 x⁴ + 2 x² + 5 x + 15 in the interval [-6,6]

$\int\limits^6_^-6} (x^{5} + 8 x^{4} + 2 x^{2} + 5 x + 15) )dx$

On integration , we get

= $(\frac{x^{6} }{6} + \frac{8 x^{5} }{5} + 2 \frac{x^{3} }{3} +\frac{5 x^{2} }{2} + 15 x)^{6} _{-6}$

$F(x) = \int\limits^a_b {f(x)} \, dx = F(b) -F(a)$

= $(\frac{6^{6} }{6} + \frac{8 6^{5} }{5} + 2 \frac{6^{3} }{3} +\frac{5 6^{2} }{2} + 15X 6) - ((\frac{(-6)^{6} }{6} + \frac{8 (-6)^{5} }{5} + 2 \frac{(-6)^{3} }{3} +\frac{5 (-6)^{2} }{2} + 15 (-6))$

After simplification and cancellation we get

= $\frac{2 X 8 X (6)^{5} }{5} + \frac{2 X 2 X (6)^3}{3} + 2 X 15 X 6$

on calculation , we get

= $\frac{124,416}{5} + \frac{864}{3} + 180$

On L.C.M 15

= $\frac{124,416 X 3 + 864 X 5 + 180 X 15}{15}$

= 25 351.2 units²

Conclusion:-

The area of the region between the graph of the given function and the x-axis = 25,351 units²

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2 years ago

Write the exact value of the side length of each square. If the value is not a whole number, estimate the length.

Savatey [412]

Given:

The area of the squares are given.

To find:

The exact side length or estimate side length of the square.

Solution:

We know that, the area of a square is

$A=a^2$

Where, a is the side length of the square.

$a=\sqrt{A}$

Area of the square is 100 square units. So, the side length is:

$a=\sqrt{100}$

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Therefore, the side length is 10 units.

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$a=\sqrt{95}$

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Therefore, the side length is between 9 and 10.

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$a=\sqrt{36}$

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Therefore, the side length is 6 units.

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What number would represent the outlier in the following set of data?

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Xelga [282]

Answer:

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Step-by-step explanation:

We can use cosine for solving this question:

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x ≈ 30.9 (Choice D)

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