Answer:
Suppose a population of rodents satisfies the differential equation dP 2 kP dt = . Initially there are P (0 2 ) = rodents, and their number is increasing at the rate of 1 dP dt = rodent per month when there are P = 10 rodents.
How long will it take for this population to grow to a hundred rodents? To a thousand rodents?
Step-by-step explanation:
Use the initial condition when dp/dt = 1, p = 10 to get k;

Seperate the differential equation and solve for the constant C.

You have 100 rodents when:

You have 1000 rodents when:

-1 will be your answer
rise over run
3-1 = 2
-4 + 1 = -3
2-1 = 1
-3 + 1 = -2
hope this helps
The answer for this question is 8 km
We know a or b != 0
but a-b==0 so both are the same unknown number
b/a must = 1
so
a/b is equivalent to b/a as a/b=1 as well.
So the last answer choice.
Answer: 1/6
Step-by-step explanation: