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Eddi Din [679]
2 years ago
5

A-project-of-construction-of-a-building-can-be-completed-by-150-workers-in-40-days-But-project-manager-brought-30-more-workers-a

fter-16-days-In-how-many-days-will-the-remaining-work-be-finished
Mathematics
1 answer:
IRINA_888 [86]2 years ago
8 0

Answer:

In the second scenario after 16 days, 150 workers would have completed 150*16=2400 worker days. That leaves 6000-2400=3600 worker days remaining. If you add 30 workers, it would take 3600/180=20 days longer to complete. So, the entire project would take 16+20=36 days to complete.

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A store is having a going -out-of buisness sale.a television set that orginally cost 3000 has been marked down by30% what do you
allsm [11]

2,247

Step-by-step explanation:

take 3000 and minus that by 30 percent, then after that, add 7 percent to get your total.

7 0
3 years ago
15 pts! Will Give Brainliest Halp! PLZ
aivan3 [116]

Theres a saying: Dividing fractions dont ask why, just flip the second and multiply.

so a/b / c/d = a/b * d/c

-8/2 * -3/6

1. cross - cancel common factor 2

4/2 * -3/3

2. Multiply

-4(-3)/ 2*3

3. multiply numbers

--12/2*3

- -12/6

4. Apply fraction rule -a/b=- a/b

=-(-12/6)

5. divide

= -(-2)

6. Apply rule -(-a)=a

=2

Your answer would be 2


3 0
3 years ago
Read 2 more answers
Help with Geometry please
balu736 [363]
It's the third one because if you look at the other ones
7 0
3 years ago
Kyle works at a donut​ factory, where a​ 10-oz cup of coffee costs 95¢​, a​ 14-oz cup costs​ $1.15, and a​ 20-oz cup costs​ $1.5
Fynjy0 [20]

Answer:

Kyle filled 4 10-oz cups, 6 14-oz cups, and 4 20-oz cups.

Step-by-step explanation:

Let 10-oz, 14-oz, and 20-oz coffees be represented by the variables <em>a, b</em>, and <em>c</em>, respectively.

Since a total of 14 cups of coffee was served:

a+b+c=14

A total of 204 ounces of coffee was served. Therefore:

10a+14b+20c=204

A total of $16.70 was collected. Hence:

0.95a+1.15b+1.5c=16.7

This yields a triple system of equations. In order to solve a triple system, we should isolate the system to only two variables first.

From the first equation, let's subtract <em>a</em> and <em>b</em> from both sides:

c=14-a-b

Substitute this into both the second and third equations:

10a+14b+20(14-a-b)=204

And:

0.95a+1.15b+1.5(14-a-b)=16.7

In this way, we've successfully created a system of two equations, which can be more easily solved. Distribute:

For the Second Equation:

\displaystyle \begin{aligned} 10a+14b+280-20a-20b&=204\\ -10a-6b&=-76\\5a+3b&=38\end{aligned}

And for the Third:

\displaystyle \begin{aligned} 0.95a+1.15b+21-1.5a-1.5b&=16.7\\ -0.55a-0.35b&=-4.3\end{aligned}

We can solve this using substitution. From the second equation, isolate <em>a: </em>

<em />\displaystyle a=\frac{1}{5}(38-3b)=7.6-0.6b<em />

Substitute into the third:

-0.55(7.6-0.6b)-0.35b=-4.3

Distribute and simplify:

-4.18+0.33b-0.35b=-4.3

Therefore:

-0.02b=-0.12\Rightarrow b=6

Using the equation for <em>a: </em>

<em />a=7.6-0.6(6)=4<em />

<em />

And using the equation for <em>c: </em>

<em />c=14-(4)-(6)=14-10=4<em />

<em />

Therefore, Kyle filled 4 10-oz cups, 6 14-oz cups, and 4 20-oz cups.

7 0
2 years ago
Please help me with this question and thank you so much for your help ​
melisa1 [442]

Answer:

CosC=0.99

Step-by-step explanation:

Cos C =adjacent /Hypothenus

=36/45

=0.99

7 0
2 years ago
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