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bezimeni [28]
3 years ago
5

Question 4 of 17

Mathematics
1 answer:
Vlada [557]3 years ago
4 0

Answer:

I think it is A OR D

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Solve y=3bx-7x for x
irina [24]
Y = 3bx - 7x
y = x(3b - 7)

Divide each side by 3b - 7 (assume that it is not zero).
\frac{y}{3b-7} =x

Answer:
x= \frac{y}{3b-7}
6 0
3 years ago
Answer this pls<br>don't send links​
Irina18 [472]

Answer:

a 20 times

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
HELP ME PLZ!!!!!!!!!!
nevsk [136]


C. No, this is not a valid inference because she asked only 35 families

4 0
3 years ago
An envelope contains three cards: a black card that is black on both sides, a white card that is white on both sides, and a mixe
Over [174]

Answer:

There is a  2/3  probability that the other side is also black.

Step-by-step explanation:

Here let B1: Event of picking a card that has a black side

B2: Event of picking a card that has BOTH black side.

Now, by the CONDITIONAL PROBABILITY:

P(B_2/B_1 )  = \frac{P(B_1\cap B_2)}{P(B_1)}

Now, as EXACTLY ONE CARD has both sides BLACK in three cards.

⇒ P (B1 ∩ B2) = 1 /3

Also, Out if total 6 sides of cards, 3 are BLACK from one side.

⇒ P (B1 ) = 3 /6 = 1/2

Putting these values in the formula, we get:

P(B_2/B_1 )  = \frac{P(B_1\cap B_2)}{P(B_1)} = \frac{1}{3}  \times\frac{2}{1} = \frac{2}{3}

⇒ P (B2 / B1)  =  2/3

Hence, there is a  2/3  probability that the other side is also black.

 

5 0
3 years ago
An investment banker deposited $50,000 in an account earning a nominal 6% per year compounded continuously. How much was in the
Orlov [11]

Answer:

The amount in the account at the end of three years will be $59,861.

Step-by-step explanation:

The formula to compute the amount at the end of <em>t</em> years, compounded continuously is:

A=P\times e^{t\times i}

Here,

A = Amount at the end

P = Principal amount

i = interest rate

t = number of years.

It is provided that:

P = $50,000

i = 6%

t = 3 years

Compute the amount in the account at the end of three years as follows:

A=P\times e^{t\times i}

   =50000\times e^{(3\times 0.06)}\\=50000\times 1.19722\\=59861

Thus, the amount in the account at the end of three years will be $59,861.

5 0
3 years ago
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