Answer:
Step 1: Our output value is 15.
Step 2: We represent the unknown value with $x$.
Step 3: From step 1 above,$15=100\%$.
Step 4: Similarly, $x=60\%$.
Step 5: This results in a pair of simple equations:
$15=100\%(1)$.
$x=60\%(2)$.
Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both
equations have the same unit (%); we have
$\frac{15}{x}=\frac{100\%}{60\%}$
Step 7: Again, the reciprocal of both sides gives
$\frac{x}{15}=\frac{60}{100}$
$\Rightarrow x=9$
Therefore, $60\%$ of $15$ is $9$Step 1: Our output value is 15.
Step 2: We represent the unknown value with $x$.
Step 3: From step 1 above,$15=100\%$.
Step 4: Similarly, $x=60\%$.
Step 5: This results in a pair of simple equations:
$15=100\%(1)$.
$x=60\%(2)$.
Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both
equations have the same unit (%); we have
$\frac{15}{x}=\frac{100\%}{60\%}$
Step 7: Again, the reciprocal of both sides gives
$\frac{x}{15}=\frac{60}{100}$
$\Rightarrow x=9$
Therefore, $60\%$ of $15$ is $9$Step 1: Our output value is 15.
Step 2: We represent the unknown value with $x$.
Step 3: From step 1 above,$15=100\%$.
Step 4: Similarly, $x=60\%$.
Step 5: This results in a pair of simple equations:
$15=100\%(1)$.
$x=60\%(2)$.
Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both
equations have the same unit (%); we have
$\frac{15}{x}=\frac{100\%}{60\%}$
Step 7: Again, the reciprocal of both sides gives
$\frac{x}{15}=\frac{60}{100}$
$\Rightarrow x=9$
Therefore, $60\%$ of $15$ is $9$Step 1: Our output value is 15.
Step 2: We represent the unknown value with $x$.
Step 3: From step 1 above,$15=100\%$.
Step 4: Similarly, $x=60\%$.
Step 5: This results in a pair of simple equations:
$15=100\%(1)$.
$x=60\%(2)$.
Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both
equations have the same unit (%); we have
$\frac{15}{x}=\frac{100\%}{60\%}$
Step 7: Again, the reciprocal of both sides gives
$\frac{x}{15}=\frac{60}{100}$
$\Rightarrow x=9$
Therefore, $60\%$ of $15$ is $9$Step 1: Our output value is 15.
Step 2: We represent the unknown value with $x$.
Step 3: From step 1 above,$15=100\%$.
Step 4: Similarly, $x=60\%$.
Step 5: This results in a pair of simple equations:
$15=100\%(1)$.
$x=60\%(2)$.
Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both
equations have the same unit (%); we have
$\frac{15}{x}=\frac{100\%}{60\%}$
Step 7: Again, the reciprocal of both sides gives
$\frac{x}{15}=\frac{60}{100}$
$\Rightarrow x=9$
Therefore, $60\%$ of $15$ is $9$Step 1: Our output value is 15.
Step 2: We represent the unknown value with $x$.
Step 3: From step 1 above,$15=100\%$.
Step 4: Similarly, $x=60\%$.
Step 5: This results in a pair of simple equations:
$15=100\%(1)$.
$x=60\%(2)$.
Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both
equations have the same unit (%); we have
$\frac{15}{x}=\frac{100\%}{60\%}$
Step 7: Again, the reciprocal of both sides gives
$\frac{x}{15}=\frac{60}{100}$
$\Rightarrow x=9$
Therefore, $60\%$ of $15$ is $9$Step 1: Our output value is 15.
Step 2: We represent the unknown value with $x$.
Step 3: From step 1 above,$15=100\%$.
Step 4: Similarly, $x=60\%$.
Step 5: This results in a pair of simple equations:
$15=100\%(1)$.
$x=60\%(2)$.
Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both
equations have the same unit (%); we have
$\frac{15}{x}=\frac{100\%}{60\%}$
Step 7: Again, the reciprocal of both sides gives
$\frac{x}{15}=\frac{60}{100}$
$\Rightarrow x=9$
Therefore, $60\%$ of $15$ is $9$Step 1: Our output value is 15.
Step 2: We represent the unknown value with $x$.
Step 3: From step 1 above,$15=100\%$.
Step 4: Similarly, $x=60\%$.
Step 5: This results in a pair of simple equations:
$15=100\%(1)$.
$x=60\%(2)$.
Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both
equations have the same unit (%); we have
$\frac{15}{x}=\frac{100\%}{60\%}$
Step 7: Again, the reciprocal of both sides gives
$\frac{x}{15}=\frac{60}{100}$
$\Rightarrow x=9$
Therefore, $60\%$ of $15$ is $9$
Step-by-step explanation:
![\lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left \{ {{y=2} \atop {x=2}} \right.](https://tex.z-dn.net/?f=%20%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20a_n%20%20%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%263%5C%5C4%265%266%5C%5C7%268%269%5Cend%7Barray%7D%5Cright%5D%20%20%20%5Cleft%20%5C%7B%20%7B%7By%3D2%7D%20%5Catop%20%7Bx%3D2%7D%7D%20%5Cright.%20)
