The table has a set of expressions representing the sums of rational and irrational numbers. Find each sum, and indicate

Mathematics

2 answers:

ipn [44]3 years ago

7 0

Answer:

$\pi +24 = irrational\\\\\sqrt{16} + (-\frac {21}{5}) = rational\\\\\sqrt{8} +\pi =irrational\\\\\sqrt{4}+5= rational\\\\\sqrt{36}+ \sqrt[3]{27} = rational$

$\frac{3}{4} + \sqrt{27} = irrational$

Step-by-step explanation:

kotegsom [21]3 years ago

4 0

Answer:

1. rational

2.irrational

3.irrational

4.rational

5.rational

6.irrational

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STatiana [176]

It’s the last one 7 sqrt5+8sqrt2/27

6 0

3 years ago

Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu

olchik [2.2K]

Answer:

a) $s^2 =30^2 =900$

b) $\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}$

$567.28 \leq \sigma^2 \leq 1690.224$

c) $23.818 \leq \sigma \leq 41.112$

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in the variability in the number of rooms occupied per day during a particular season of the year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

$s^2 =30^2 =900$

Part b

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$