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SVEN [57.7K]
3 years ago
9

How do you write 37,015.08 in expanded form

Mathematics
1 answer:
kondaur [170]3 years ago
3 0

Answer:

Thirty-seven thousand fifteen and eight hundredths

Step-by-step explanation:

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NEED HELP ASAP!!!
Kay [80]
A

sorry if its wrong looks reasonable
6 0
3 years ago
after selling three fifth of its books, a bookstore had 880 textbooks left. how many books were in the bookstore initially
sleet_krkn [62]

Answer:

yours answer is 1760

Step-by-step explanation:

he sold 3/5 of its books , that means 2/5 is left and 2/5 is 880

so 2/5=880  


880/5 = 176

176x2=352


352x5=1760

5 0
3 years ago
Evaluate <br> |-9|= <br><br> Please helpp
miv72 [106K]

Answer:

9

Step-by-step explanation:

How to solve your question

Your question is

|

−

9

|

|-9|

∣−9∣

Solve

1

Find the absolute value

|

−

9

|

9

Solution

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6 0
3 years ago
Read 2 more answers
Find the solution to the equation below.<br> 2x^2+3x-20=0
mariarad [96]

Answer:

  x = -4, 5/2

Step-by-step explanation:

A quadratic can be solved may ways, including graphing, factoring, and the quadratic formula. You can also check possible answers by making use of the relationships between solutions and the coefficients.

__

A graph is attached. It shows the solutions to be -4 and 5/2.

__

When factored, the equation becomes ...

  (2x -5)(x +4) = 0 . . . . . has solutions x=-4, x=5/2 (these make the factors zero)

__

Using the quadratic formula, the solutions of ax^2 +bx +c = 0 are found from ...

  x = (-b±√(b²-4ac))/(2a)

  x = (-3±√(3²-4(2)(-20))/(2(2)) = (-3±√169)/4 = {-16, +10}/4

  x = {-4, 5/2}

__

For ax^2 +bx +c = 0, the solutions must satisfy ...

  product of solutions is c/a = -20/2 = -10

Only the first and last choices have this product.

  sum of solutions is -b/a = -3/2

Only the first choice (-4, 5/2) has this sum.

8 0
3 years ago
The equation tan^2 x+1=sec^2 x is an identity true or false
Solnce55 [7]

Answer:

tan²x + 1 = sec²x is identity

Step-by-step explanation:

* Lets explain how to find this identity

∵ sin²x + cos²x = 1 ⇒ identity

- Divide both sides by cos²x

∵ sin x ÷ cos x = tan x

∴ sin²x ÷ cos²x = tan²x

- Lets find the second term

∵ cos²x ÷ cos²x = 1

- Remember that the inverse of cos x is sec x

∵ sec x = 1/cos x

∴ sec²x = 1/cos²x

- Lets write the equation

∴ tan²x + 1 = 1/cos²x

∵ 1/cos²x = sec²x

∴ than²x + 1 = sec²x

- So we use the first identity sin²x + cos²x = 1 to prove that

 tan²x + 1 = sec²x

∴ tan²x + 1 = sec²x is identity

8 0
3 years ago
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