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bogdanovich [222]
3 years ago
15

Which are the solutions of x2 = 19x 1

Mathematics
2 answers:
o-na [289]3 years ago
8 0
Here you go.

I was sorta unsure how to read the last part in your question but I tried my best to interpret it 

irga5000 [103]3 years ago
7 0

For this case we have the following quadratic equation:

x ^ 2 = 19x + 1

Rewriting we have:

x ^ 2 - 19x - 1 = 0

Then, using the quadratic formula we have:

x =\frac{-b+/-\sqrt{b^2-4ac}}{2a}

Substituting values:

x =\frac{-(-19)+/-\sqrt{(-19)^2-4(1)(-1)}}{2(1)}

Rewriting:

x =\frac{19+/-\sqrt{361+4}}{2}

x =\frac{19+/-\sqrt{365}}{2}

Therefore, the solutions are given by:

x =\frac{19+\sqrt{365}}{2}

x =\frac{19-\sqrt{365}}{2}

Answer:

The solutions of the equation are:

x =\frac{19+\sqrt{365}}{2}

x =\frac{19-\sqrt{365}}{2}

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Answer:

b = 1

Step-by-step explanation:

8 = b - 1 + 8b

<em>combine like terms</em>

8 = 9b - 1

<em>add 1 to both sides of the equation</em>

<em>8 + 1 = 9b - 1 + 1</em>

<em>8 + 1 = 9b</em>

9 = 9b

<em>divide both sides of the equation by 9</em>

9/9 = 9b/9

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<em />

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Describe the steps to dividing imaginary numbers and complex numbers with two terms in the denominator?
zlopas [31]

Answer:

Let be a rational complex number of the form z = \frac{a + i\,b}{c + i\,d}, we proceed to show the procedure of resolution by algebraic means:

1) \frac{a + i\,b}{c + i\,d}   Given.

2) \frac{a + i\,b}{c + i\,d} \cdot 1 Modulative property.

3) \left(\frac{a+i\,b}{c + i\,d} \right)\cdot \left(\frac{c-i\,d}{c-i\,d} \right)   Existence of additive inverse/Definition of division.

4) \frac{(a+i\,b)\cdot (c - i\,d)}{(c+i\,d)\cdot (c - i\,d)}   \frac{x}{y}\cdot \frac{w}{z} = \frac{x\cdot w}{y\cdot z}  

5) \frac{a\cdot (c-i\,d) + (i\,b)\cdot (c-i\,d)}{c\cdot (c-i\,d)+(i\,d)\cdot (c-i\,d)}  Distributive and commutative properties.

6) \frac{a\cdot c + a\cdot (-i\,d) + (i\,b)\cdot c +(i\,b) \cdot (-i\,d)}{c^{2}-c\cdot (i\,d)+(i\,d)\cdot c+(i\,d)\cdot (-i\,d)} Distributive property.

7) \frac{a\cdot c +i\,(-a\cdot d) + i\,(b\cdot c) +(-i^{2})\cdot (b\cdot d)}{c^{2}+i\,(c\cdot d)+[-i\,(c\cdot d)] +(-i^{2})\cdot d^{2}} Definition of power/Associative and commutative properties/x\cdot (-y) = -x\cdot y/Definition of subtraction.

8) \frac{(a\cdot c + b\cdot d) +i\cdot (b\cdot c -a\cdot d)}{c^{2}+d^{2}} Definition of imaginary number/x\cdot (-y) = -x\cdot y/Definition of subtraction/Distributive, commutative, modulative and associative properties/Existence of additive inverse/Result.

Step-by-step explanation:

Let be a rational complex number of the form z = \frac{a + i\,b}{c + i\,d}, we proceed to show the procedure of resolution by algebraic means:

1) \frac{a + i\,b}{c + i\,d}   Given.

2) \frac{a + i\,b}{c + i\,d} \cdot 1 Modulative property.

3) \left(\frac{a+i\,b}{c + i\,d} \right)\cdot \left(\frac{c-i\,d}{c-i\,d} \right)   Existence of additive inverse/Definition of division.

4) \frac{(a+i\,b)\cdot (c - i\,d)}{(c+i\,d)\cdot (c - i\,d)}   \frac{x}{y}\cdot \frac{w}{z} = \frac{x\cdot w}{y\cdot z}  

5) \frac{a\cdot (c-i\,d) + (i\,b)\cdot (c-i\,d)}{c\cdot (c-i\,d)+(i\,d)\cdot (c-i\,d)}  Distributive and commutative properties.

6) \frac{a\cdot c + a\cdot (-i\,d) + (i\,b)\cdot c +(i\,b) \cdot (-i\,d)}{c^{2}-c\cdot (i\,d)+(i\,d)\cdot c+(i\,d)\cdot (-i\,d)} Distributive property.

7) \frac{a\cdot c +i\,(-a\cdot d) + i\,(b\cdot c) +(-i^{2})\cdot (b\cdot d)}{c^{2}+i\,(c\cdot d)+[-i\,(c\cdot d)] +(-i^{2})\cdot d^{2}} Definition of power/Associative and commutative properties/x\cdot (-y) = -x\cdot y/Definition of subtraction.

8) \frac{(a\cdot c + b\cdot d) +i\cdot (b\cdot c -a\cdot d)}{c^{2}+d^{2}} Definition of imaginary number/x\cdot (-y) = -x\cdot y/Definition of subtraction/Distributive, commutative, modulative and associative properties/Existence of additive inverse/Result.

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2 years ago
WILL GIVE BRAINLIEST
scoray [572]
Inverse Variation is shown through the formula y=k/x
plug in the given values and solve for k: 3=k/5 so k=15

Answer: y=15/x
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