Answer:
Step-by-step explanation:
T = 4c + 25....where c = # of classes and T = total cost
2 classes...so sub in 2 for c and solve for T
T = 4(2) + 25
T = 8 + 25
T = 33 <==== with 2 classes ,its $ 33
4 classes....so sub in 4 for c and solve for T
T = 4(4) + 25
T = 16 + 25
T = 41 <==== with 4 classes, its $ 41
8 classes....sub in 8 for c
T = 4(8) + 25
T = 32 + 25
T = $ 57 <==== with 8 classes, its $ 57
10 classes...sub in 10 for c
T = 4(10) + 25
T = 40 + 25
T = 65 <===== with 10 classes, its $ 65
Answer:
$14.8
Step-by-step explanation:
There is a mistype in the question. It should say: ... <em>si cada uno de ellos hicieron una contribución de </em><em>dieciseis</em><em> pesos...</em>
So if everybody contributes $14, they make a total of 14*x, where x denotes the number of students. In this scenario, $4 are left, calling y to the cost of the trip, then:
14*x = y - 4 (eq. 1)
In the other scenario, everybody contributes $16 and $6 are in excess, so
16*x = y + 6 (eq. 2)
subtracting eq. 1 to eq. 2:
16*x - 14*x = y + 6 - (y - 4)
2*x = y + 6 - y + 4
2*x = 10
x = 10/2 = 5
Replacing this value in eq. 1:
14*5 = y - 4
70 + 4 = y
y = $74
If every student pays: 74/5 = $14.8, then they would get altogether the exact cost of the trip
Answer:
<u>Its a monomial of degree 0</u>
Step-by-step explanation:
pls mark brainliest
Answer:
I am pretty sure its 30 students
