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Lyrx [107]
2 years ago
13

La longitud de una sala excede a su ancho en 4 m si cada dimensión se aumenta en 4 m el área sera el doble. Hallar las dimension

es de la sala.
Mathematics
1 answer:
Nadusha1986 [10]2 years ago
6 0

Answer:

G

Step-by-step explanation:

dx bkydh

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-4x + 1ly = 15<br>x = 2y x = y =​
sertanlavr [38]

Answer: you wrote it wrong

Step-by-step explanation:

6 0
2 years ago
During 2002, the average person ate 200.8 pounds of meat. How much meat does a family of 3 people eat in year?
dem82 [27]
Hi there! An average person ate 200.8 pounds of meat, so we would multiply that number by 3 to see how much meat the family ate altogether. 200.8 * 3 is 602.4. There. A family of 3 would eat 602.4 pounds of meat in a year.
4 0
3 years ago
Read 2 more answers
If your dog weighs 32 kilograms (kg), how many milligrams (mg) is this?
Tatiana [17]

Answer:

milligram would be 3.2e+7 or if not 3.2

7 0
2 years ago
Read 2 more answers
I NEED NUMBER 24 ONLY PLEASEEEEEEEEEEEE I NEED HELP I DON’T GET IT!!!!!!
siniylev [52]

Answer:

$325,120.00

Step-by-step explanation:

This is my first answer so hopefully I do this correctly. In essence it's exactly the same as number 22!

The realtor earns $10,566.40 off of a comission of 3.25%. A comission is pretty much just a cut of however much the house cost; which a realtor gets for helping to sell the property. So we could say that the comission is equal to 3.25% of however much the house cost.

Say the house price = $x, so our equation would be:

$10,566.40 = (3.25%)•($x) or

10,566.40 = (.0325)•($x)

By solving for x we get:

$x = (10,566.40)÷(.0325) = $325,120

4 0
3 years ago
Read 2 more answers
A survey showed that 77% of us need correction (eyeglasses, contacts, surgery, etc.) for their eyesight. 13 adults are randomly
earnstyle [38]

Using the binomial distribution, it is found that the probability that at least 12 of the 13 adults require eyesight correction is of 0.163 = 16.3%. Since this probability is greater than 5%, it is found that 12 is not a significantly high number of adults requiring eyesight correction.

For each person, there are only two possible outcomes, either they need correction for their eyesight, or they do not. The probability of a person needing correction is independent of any other person, hence, the binomial distribution is used to solve this question.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • A survey showed that 77% of us need correction, hence p = 0.77.
  • 13 adults are randomly selected, hence n = 13.

The probability that at least 12 of them need correction for their eyesight is given by:

P(X \geq 12) = P(X = 12) + P(X = 13)

In which:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 12) = C_{13,12}.(0.77)^{12}.(0.23)^{1} = 0.1299

P(X = 13) = C_{13,13}.(0.77)^{13}.(0.23)^{0} = 0.0334

Then:

P(X \geq 12) = P(X = 12) + P(X = 13) = 0.1299 + 0.0334 = 0.163

The probability that at least 12 of the 13 adults require eyesight correction is of 0.163 = 16.3%. Since this probability is greater than 5%, it is found that 12 is not a significantly high number of adults requiring eyesight correction.

More can be learned about the binomial distribution at brainly.com/question/24863377

7 0
2 years ago
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