The domain of the function is all real numbers, the range of a function is y ≤ 4
<h3>What is a function?</h3>
It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.
We have a function:
f(x) = –(x + 6)(x + 2)
If we plot this function on the coordinate plane, we will see it is a graph of a quadratic function.
Here the no other details are given.
But we can say:
- The domain of the function is all real numbers.
- The range of a function is y ≤ 4
- The x-axis intercept will be at (-6, 0) and (-2, 0).
Thus, the domain of the function is all real numbers, the range of a function is y ≤ 4
Learn more about the function here:
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Answer:
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Step-by-step explanation:
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X² + 8x +y² - 2y -64 =0
We see that the equation has x² and y² . Also we see that coefficients in front of x² and y² are equal. So this is an equation of the circle.
(x² + 8x) +(y² - 2y) -64 =0
(x² + 8x) +(y² - 2y) = 64
We need to complete square for x and y groups, that means it should be written in form (a+b)² or (a-b)².
Expressions in parenthesis we will write as a²+/-2ab+b², to write it after as (a+/-b)², because a²+/-2ab+b² = (a+/-b)²
(x² + 2*4x) +(y² - 2*1y) = 64
(x² + 2*4x+4²) +(y² - 2*1y+1²) = 64+4²+1²
(x+4)² + (y-1)²= 81 Sometimes this is called a standard form of the circle.
(x+4)² + (y-1)²= 9² Sometimes it is required to write like this.
And if you are studying circles,ellipses and hyperbolas, the standard form should look like
(x1, y1) (x2, y2)
(-4, 5) (-1, 1)
x2-x1
-1 - -4
-1+4
3
y2-y1
1- -4
1+4
5
answer : (3,5)
I believe this is right, hope this helps!
Answer:
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Step-by-step explanation:
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