Answer:
<u>Window.java</u>
- public class Window {
- int width;
- int height;
-
- public Window(int width, int height){
- this.width = width;
- this.height = height;
- }
- public int getWidth(){
- return width;
- }
- public int getHeight(){
- return height;
- }
-
- public int getClientAreaHeight(){
- return getHeight();
- }
- }
<u>Main.java</u>
- public class Main {
- public static void main (String [] args) {
- Window win1 = new Window(12, 15);
- System.out.println(win1.getClientAreaHeight());
- }
- }
Explanation:
<u>Window.java</u>
There is a Window class with two int type attributes, width and height (Line 1 - 3).
The constructor of this class will take two inputs, width and height and set these input to its attributes (Line 5 - 8). There are two methods getWidth and getHeight which will return the value of attributes width and height, respectively (Line 10 - 16).
The required new method getClientAreaHeight is defined in line 18 -20. This method will call the getHeight method to return the height value of the window (Line 19).
<u>Main.java</u>
We test the Window class by creating one Window instance and call the getClientAreaHeight method and print the return output (Line 1 -6).
We shall see 15 is printed.
Im pretty sure that the correct answer is Transition words.
Based on the information given the data should be stored in flash memory.
<h3>
What is flash memory:</h3>
Flash memory is a memory storage space that is used to store data or information on a computer.
Flash memory is vital as it help to retain information or data that are stored on a computer after power is removed which inturn means that store data can be retrieve when needed.
Example of flash memory are:
Inconclusion the data should be stored in flash memory.
Learn more about flash memory here:brainly.com/question/6835146
Answer:
The correct Answer is 0.0571
Explanation:
53% of U.S. households have a PCs.
So, P(Having personal computer) = p = 0.53
Sample size(n) = 250
np(1-p) = 250 * 0.53 * (1 - 0.53) = 62.275 > 10
So, we can just estimate binomial distribution to normal distribution
Mean of proportion(p) = 0.53
Standard error of proportion(SE) =
=
= 0.0316
For x = 120, sample proportion(p) =
=
= 0.48
So, likelihood that fewer than 120 have a PC
= P(x < 120)
= P( p^ < 0.48 )
= P(z <
) (z=
)
= P(z < -1.58)
= 0.0571 ( From normal table )