Answer:
LLgg, Llgg , two out of 16
Explanation:
Given,
Dominant - Long wings and Gray color
Recessive - Short wings and Brown color
Let the allele for long wings be "L" and the allele for short wings be "l".
Let the allele for brown color be "g" and allele for gray color be "G"
Genotype of parents
LlGg
Gametes of the parent
LG, Lg, lG, lg
Dihybrid cross is between LlGg and LlGg
The offspring produces will be as follows -
LG Lg lG lg
LG LLGG LLGg LlGG LlGg
Lg LLGg LLgg LlGg Llgg
lG LlGG LlGg llGG llGg
lg LlGg Llgg llGg llgg
Offspring with long wings and brown color – LLgg, Llgg , two out of 16
Answer: What are you asking??
Answer:
G=21 %
T= 29 %
A= 29 %
Explanation:
Since C only binds to G, you have the same amount of C and G, so G is 21 %.
100 % minus 42 % ( 21 % C plus 21 % G=) equals 58 %.
So the other 58 % is made of T and A. Since T only binds to A , the half of the extra 58 % is T and the other half is A. Therefore 29 % is T and 29 % is A
Addition or deletion of nucleotides in any number besides 3 results in a "frame-shift mutation."
This is because every 3 nucleotides of DNA/mRNA exons codes for a single amino acid in the synthesis of a protein. This triplet codon theory means that if 3 nucleotides are added or deleted then an amino acid will be added or lost, but subsequent codons and amino acids will still be read correctly.
However, if any number of nucleotides other than 3 are added or removed, then the codons following the mutation will be out of "sync," in terms of the reading order.
Hence it is called a frame-shift mutation because it shift the reading frame when translating nucleic acids into proteins. Frame shifts will lead to the wrong amino acids being adding in the wrong order for the rest of the code after the mutation.
