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2 years ago

Can someone please help me I really need help !!!

Mathematics

2 answers:

Viefleur [7K]2 years ago

7 0

Answer:

you can search on G*ogle. Thanks

yanalaym [24]2 years ago

6 0

Answer:sure!

Step-by-step explanation:

your answer is below

we have angles

and

so the complemantary is 90

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Find the distance between the pair of points<br><br> (0,0)(6,8)

Ivahew [28]

A(0,0)
B=(6,8)

Distance formula

$\boxed{\sf AB=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}$

$\\ \sf\longmapsto \sqrt{(6 - 0) {}^{2} + {(8 - 0)}^{2} } \\ \\ \sf\longmapsto \sqrt{ {6}^{2} + {8}^{2} } \\ \\ \sf\longmapsto \sqrt{36 + 64 } \\ \\ \sf\longmapsto \sqrt{100} \\ \\ \sf\longmapsto 10$

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3 years ago

What is the distance between (-6,8) and (-3,9)?

yKpoI14uk [10]

The midpoint is: (-4.5,8.5)

3 0

3 years ago

Read 2 more answers

The midpoint of AB is (3,2). If point is is located at(8,4) what are the coordinates of point B

Dmitry [639]

Step-by-step explanation:

8-3 = 5,

3-5 = -2 = the x coordinate of B

-2-4 =-6,

-2-6 =-8 = the y coordinate of B

(-2,-8) is the point B

A is 5 to the right of the midpoint, so B is 5 to the left of the midpoint

A is 6 up from the midpoint so B is 6 down from the midpoint

7 0

2 years ago

Ummm can someone plsss help, i need this to bring my grade up!!?

artcher [175]

Answer:

I would say it would also be 64 degrees because if you flip the HGJ to the IJG it would be the same! Hope this helps

8 0

3 years ago

Read 2 more answers

A 2.2 kg ball strikes a wall with a velocity of 7.4 m/s to the left. The ball bounces off with a velocity of 6.2 m/s to the righ

Naya [18.7K]

Answer:

The constant force exerted on the ball by the wall is 119.68 N.

Step-by-step explanation:

Consider the provided information.

It is given that the mass of the ball is m = 2.2 kg

The initial velocity of the ball towards left is 7.4 m/s

So the momentum of the ball when it strikes is = $2.2\times 7.4=16.28$

The final velocity of the ball is -6.2 m/s

So the momentum of the ball when it strikes back is = $2.2\times -6.2=-13.64$

Thus change in moment is: $16.28-(-13.64)=29.92$

The duration of force exerted on the ball t = 0.25 s

Therefore, the constant force exerted on the ball by the wall is:

$\frac{29.92}{0.25}=119.68$

Hence, the constant force exerted on the ball by the wall is 119.68 N.

6 0

3 years ago