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SOVA2 [1]
3 years ago
8

PLEASE HELP, NEEDS TO BE COMPLETED TODAY!

Mathematics
1 answer:
vesna_86 [32]3 years ago
5 0
Using a graph tool

case 1) 
2x-y=-13
y=x+9
the solution is the point (-4,5)
see the attached figure N 1

case 2)
y=3x-7
y=2x-5
the solution is the point (2,-1)
see the attached figure N 2

case 3)
3x+2y=10
6x-y=10
the solution is the point (2,2)
see the attached figure N 3

case 4)
y=6
x=-5
the solution is the point (-5,6)
see the attached figure N 4

case 5)
4x-3y=5
3x+2y=-9
the solution is the point (-1,-3)
see the attached figure N 5

case 6)
x+y=7
x-y=-1
the solution is the point (3,4)
see the attached figure N 6

the answer in the attached figure

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Solve for
Lubov Fominskaja [6]

Answer:

x = 3/2

Step-by-step explanation:

2(x + 5) = 6x + 4

Open bracket first

2 × x + 2×5 = 6x + 4

2x + 10 = 6x + 4

Rewrite equation

6x + 4 = 2x + 10

Subtract 2x from both sides

6x - 2x + 4 = 2x - 2x + 10

4x + 4 = 10

Subtract 4 from both sides

4x + 4 - 4 = 10 - 4

4x = 6

Divide both sides by 4

4x/4 = 6/4

x = 6/4

Divide both denominator and numerator by 2

x = (6/4) ÷ 2

x = 3/2

I hope this was helpful, please rate as brainliest  

7 0
3 years ago
Rita earns $17.00 per hour. If she gets a 6% raise, what will be her new hourly wage?
ipn [44]

multiply 17 by 6%

17 * 0.06 = 1.02 increase

17 +1.02 = 18.02 new hourly wage

8 0
3 years ago
Explain what 78.5% would look like on a 100% block. Then write it as a decimal.
Gennadij [26K]
78.5/100 as a decimal is just 0.78.5 and as a percent it is 78.5 %

5 0
3 years ago
Read 2 more answers
What is the center of the circle that you can circumscribe about a triangle with vertices A(2, 6), B(2, 0), and C(10, 0)?
denis23 [38]
The three points A,B,C are all points on this circle.
Each point is then equal distance from the center, that distance being the radius of the circle.
Using the distance formula, we can find the center of the circle  (x,y):
d^2 = (x-x_0)^2 + (y-y_0)^2
Plugging in points A and B into distance formula, then setting them equal to each other gives:
(x-2)^2+(y-6)^2 = (x-2)^2 + y^2
Right away we can cancel out the x terms leaving:
(y-6)^2 = y^2
Expand Left side and Solve for y:
y^2 -12y +36 = y^2
y = 3
Plug in points B and C as before:
(x-2)^2 + y^2 = (x-10)^2 + y^2
Here we can cancel the y-terms.
Expand and solve for x:
x^2 -4x+4 = x^2 -20x+100
16x = 96
x = 6
Therefore the center of the circle is the point (6,3)
6 0
3 years ago
If the domain of the function f(x) = x - 5 is {1, 3, 4, 6} what is the range? F
Margarita [4]

Answer:

-4, -2, -1, 1

Step-by-step explanation:

If the domain is given we use the equation to determine the range but usually the range would be everything in this equation.

7 0
3 years ago
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