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Kobotan [32]
3 years ago
10

A person is watching a boat from the top of a lighthouse. The boat is approaching the lighthouse directly. When first noticed, t

he angle of depression to the boat is 16°18'. When the boat stops, the angle of depression is 48°51'. The lighthouse is 200 feet tall. How far did the boat travel from when it was first noticed until it stopped? Round your answer to the hundredths place.

Mathematics
1 answer:
Zina [86]3 years ago
6 0

check the picture below.


bearing in mind that there are 60 minutes in 1 degree, then 16°18' will be 16.3° and likewise 48°51' will be 48.85° if we convert those to degrees only.


\bf y=\cfrac{200}{tan(48.85^o)}~\hspace{10em}x=\cfrac{200}{tan(16.3^o)}-y \\\\\\ x=\cfrac{200}{tan(16.3^o)}-\cfrac{200}{tan(48.85^o)}\implies x\approx 683.95 - 174.78\implies x\approx 509.17

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Answer:

Width = 4ft

Height = 4ft

Length = 8ft

Step-by-step explanation:

Given

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L = 2W

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Required

The dimension that minimizes the cost

The volume is:

Volume = LWH

This gives:

128 = LWH

Substitute L = 2W

128 = 2W * WH

128 = 2W^2H

Make H the subject

H = \frac{128}{2W^2}

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The surface area is:

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So, we have:

A = LW + 2(WH + LH)

The cost is:

Cost = 9 * LW + 6 * 2(WH + LH)

Cost = 9 * LW + 12(WH + LH)

Cost = 9 * LW + 12H(W + L)

Substitute: H = \frac{64}{W^2} and L = 2W

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To minimize the cost, we differentiate

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36W = 2304W^{-2}

Divide both sides by W

36 = 2304W^{-3}

Rewrite as:

36 = \frac{2304}{W^3}

Solve for W^3

W^3 = \frac{2304}{36}

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W = 4

Recall that:

L = 2W

L = 2 * 4

L = 8

H = \frac{64}{W^2}

H = \frac{64}{4^2}

H = \frac{64}{16}

H = 4

Hence, the dimension that minimizes the cost is:

Width = 4ft

Height = 4ft

Length = 8ft

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