<u><em>The answer:</em></u> 6x^3+18x
<u><em>The Explanation:</em></u> You need to uses distributive property to 6x to x^2+3 which will be 6x^3+18x
The correct answer is 4 :-)
Given:
The expression is

To find:
The expression in repeated multiplication form and then write the expression as a power.
Solution:
We have,

The repeated multiplication form of this expression is
![=[(-8)\cdot (-8)\cdot (-8)]\cdot [(-8)\cdot (-8)\cdot (-8)\cdot (-8)]](https://tex.z-dn.net/?f=%3D%5B%28-8%29%5Ccdot%20%28-8%29%5Ccdot%20%28-8%29%5D%5Ccdot%20%5B%28-8%29%5Ccdot%20%28-8%29%5Ccdot%20%28-8%29%5Ccdot%20%28-8%29%5D)

Clearly, (-8) is multiplied seven times by itself. So,

Therefore, the repeated multiplication form of the given expression is
and the expression as single power is
.
Answer:
80 feet
Step-by-step explanation:
Given:
Initial speed of the car (
) = 40 ft/sec
Deceleration of the car (
) = -10 ft/sec²
Final speed of the car (
) = 0 ft/sec
Let the distance traveled by the car be 'x' at any time 't'. Let 'v' be the velocity at any time 't'.
Now, deceleration means rate of decrease of velocity.
So, 
Negative sign means the velocity is decreasing with time.
Now,
using chain rule of differentiation. Therefore,

Integrating both sides under the limit 40 to 0 for 'v' and 0 to 'x' for 'x'. This gives,
![\int\limits^0_{40} {v} \, dv=\int\limits^x_0 {-10} \, dx\\\\\left [ \frac{v^2}{2} \right ]_{40}^{0}=-10x\\\\-10x=\frac{0}{2}-\frac{1600}{2}\\\\10x=800\\\\x=\frac{800}{10}=80\ ft](https://tex.z-dn.net/?f=%5Cint%5Climits%5E0_%7B40%7D%20%7Bv%7D%20%5C%2C%20dv%3D%5Cint%5Climits%5Ex_0%20%7B-10%7D%20%5C%2C%20dx%5C%5C%5C%5C%5Cleft%20%5B%20%5Cfrac%7Bv%5E2%7D%7B2%7D%20%5Cright%20%5D_%7B40%7D%5E%7B0%7D%3D-10x%5C%5C%5C%5C-10x%3D%5Cfrac%7B0%7D%7B2%7D-%5Cfrac%7B1600%7D%7B2%7D%5C%5C%5C%5C10x%3D800%5C%5C%5C%5Cx%3D%5Cfrac%7B800%7D%7B10%7D%3D80%5C%20ft)
Therefore, the car travels a distance of 80 feet before stopping.
Answer:
Step-by-step explanation:
= 19 R 15
= 19 15/17
338 divided by 17 equals
19 with a remainder of 15
Solution:
0 1 9
1 7 {3 3 8
− {0
3 3
− 1 7
1 6 8
− 1 5 3
1 5
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