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2 years ago

1 point

Physics

1 answer:

Vlad [161]2 years ago

5 0

Answer:

PE=0

Explanation:

If the tank is on the ground, there is 0 height which means the equation of PE=mh will be PE=12543(0)=0, hope this helps!

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Find the following answer based on the image.

saul85 [17]

<u>We are given:</u>

Mass of Neptune = 1.03 * 10²⁶ kg

Distance from the center of Neptune (r) = 2.27 * 10⁷

now, computing the value of the acceleration due to gravity (g)

<u>Finding g:</u>

We know the formula:

g = G(mass of planet) / (r)²

g = [6.67 * 10⁻¹¹ * 1.03*10²⁶] / (2.27*10⁷) [since G is 6.67*10⁻¹¹]

g = (6.87 * 10¹⁵) / (5.15 * 10¹⁴)

which can be rewritten as:

g = (6.87 * 10¹⁵ * 10⁻¹⁴) / 5.15

g = (6.87 * 10¹⁵⁻¹⁴) / 5.15

g = (6.87/5.15) * 10

g = 1.34 * 10

g = 13.4 m/s² <em>(approx)</em>

5 0

3 years ago

The average lifetime of a poodle dog is 13.0 years. How fast is it traveling, u, relative to an observer who measures the averag

bogdanovich [222]

Answer:

The speed is 0.97 c.

Explanation:

Given that,

Dilated time t'= 50.0 years

Rest time t = 13.0 years

We need to calculate the speed

Using formula of time dilation

$t'=\dfrac{t}{\sqrt{1-\dfrac{v^2}{c^2}}}$

Where, t' = change in time

t = rest time

v = velocity

c = speed of light

Put the value into the formula

$50.0=\dfrac{13.0}{\sqrt{1-\dfrac{v^2}{(3\times10^{8})^2}}}$

$v^2=\dfrac{(13)^2\times(c)^2-(c)^2\times50^2}{50^2}$

$v^2= 0.9324c^2$

$v=0.97c$

Hence, The speed is 0.97 c.

6 0

3 years ago

Determine the distance from the Earth's center to a point outside the Earth where the gravitational acceleration due to the Eart

Temka [501]

The distance from the Earth's center to the point outside the Earth is 55800 Km

<h3>How to determine the distance from the surface of the Earth</h3>

Acceleration due to gravity of Earth = 9.8 m/s²
Acceleration due to gravity of the poin (g) = 1/60 × 9.8 = 0.163 m/s²
Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²
Mass of the Earth (M) = 5.97×10²⁴ Kg
Distance from the surface of the Earth (r) =?

g = GM / r²

Cross multiply

GM = gr²

Divide both sides by g

r² = GM / g

Take the square root of both sides

r = √(GM / g)

r = √[(6.67×10¯¹¹ × 5.97×10²⁴) / 0.163)]

r = 4.94×10⁷ m

Divide by 1000 to express in Km

r = 4.94×10⁷ / 1000

r = 4.94×10⁴ Km

<h3>How to determine the distance from the center of the Earth</h3>

Distance from the surface of the Earth (r) = 4.94×10⁴ Km
Radius of the Earth (R) = 6400 Km
Distance from the centre of the Earth =?

Distance from the centre of the Earth = R + r

Distance from the centre of the Earth = 6400 + 4.94×10⁴

Distance from the centre of the Earth = 55800 Km

Learn more about gravitational force:

brainly.com/question/21500344

#SPJ1

5 0

2 years ago

A force of 10N is applied by a boy while lifting a 20,000g mass. How much does it accelerate by?

Tanya [424]

Answer:

0.5 $m/s^{2}$

Explanation:

20000g to kg = $\frac{20000}{1000}$ = 20 kg

f = ma

a = $\frac{f}{m}$

a = $\frac{10}{20}$

a = $\frac{1}{2}$

a = 0.5 $m/s^{2}$

8 0

3 years ago

For a certain ideal Carnot engine, the hot reservoir is 35°C higher than the cold reservoir. If this engine is to have an effici

lord [1]

Answer:

Temperature of the hot reservoir is 1540K

Explanation:

$E= 1- \frac{T_{c}}[tex]{T_h}=308+{T_c}\\Efficiency of a carnot engine is given by the aboveTc=temperature of the cold reservoirTh= temperature of the hot reservoirK=273+ 35 (convert 35°C to kelvin)K=308k{T_h}={T_c}+308-----------------------(equation 1)20%=1-{T_c}/{T_h}$

0.2=({T_c}+308-{T_c})/{T_c}+308

.2({T_c}+61.6=308

0.2{T_c}=246.4

{T_c}=1232

recall from equation 1

{T_h}=308+1232

{T_h}=1540K

5 0

3 years ago