Question

Determine the distance from the Earth's center to a point outside the Earth where the gravitational acceleration due to the Earth is 1/60 of its value at the Earth's surface.

Answer 1

The distance from the Earth's center to the point outside the Earth is 55800 Km

How to determine the distance from the surface of the Earth

• Acceleration due to gravity of Earth = 9.8 m/s²
• Acceleration due to gravity of the poin (g) = 1/60 × 9.8 = 0.163 m/s²
• Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²
• Mass of the Earth (M) = 5.97×10²⁴ Kg
• Distance from the surface of the Earth (r) =?

g = GM / r²

Cross multiply

GM = gr²

Divide both sides by g

r² = GM / g

Take the square root of both sides

r = √(GM / g)

r = √[(6.67×10¯¹¹ × 5.97×10²⁴) / 0.163)]

r = 4.94×10⁷ m

Divide by 1000 to express in Km

r = 4.94×10⁷ / 1000

r = 4.94×10⁴ Km

How to determine the distance from the center of the Earth

• Distance from the surface of the Earth (r) = 4.94×10⁴ Km
• Radius of the Earth (R) = 6400 Km
• Distance from the centre of the Earth =?

Distance from the centre of the Earth = R + r

Distance from the centre of the Earth = 6400 + 4.94×10⁴

Distance from the centre of the Earth = 55800 Km

Learn more about gravitational force:

brainly.com/question/21500344

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