3 years ago

Activity: Lab safety and Equipment Puzzle

Physics

1 answer:

koban [17]3 years ago

5 0

Answer:

number 2 down is: safetygoggles

Explanation:

no space

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$V=IR$
where V is the potential difference applied on the wire, I the current and R the resistance. For the resistor in the problem we have:
$R= \frac{V}{I}= \frac{5.70 V}{17.6 A}=0.32 \Omega$

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$\rho = \frac{RA}{L}$
Where A is the cross-sectional area of the wire and L its length.
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