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Zepler [3.9K]
1 year ago
13

Find the measure of each missing angle in the parallel lines and transversals below

Mathematics
1 answer:
never [62]1 year ago
6 0

The equation is 10x=2x+60

 x=15/2

∠CFH=75

∠CBD= 75

We are dealing with parallel lines, which are the lines that are equidistant to each other and never meet,  will never meet, when such lines are crossed by another line called the transversal creates many angles such as corresponding angles, vertical angles, alternate interior angles, alternate exterior angles, consecutive angles.

Since, angle CBD and angle CFH are the corresponding angles and they are equal to each other, we are given CBD=2x+60 and CFH = 10x

therefore , 10x=2x+60

=>10x-2x=60

=>8x=60

x=15/2

So, the angle CBD= 2x+60= 2(15/2)+60=  75

and the angle CFH = 10x= 10(15/2)= 75

To know more about  parallel lines refer to the link brainly.com/question/16701300?referrer=searchResults.

#SPJ1

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Answer:

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Step-by-step explanation:

An ellipse centered a point (h,k) has the following formula:

\frac{(x-h)^{2}}{a^{2}}+\frac{(y-k)^{2}}{b^{2}}=1

The distance between foci is:

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The center of the ellipse is:

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C(x,y) = (0,0)

The known vertex is on the horizontal axis of the ellipse. Then, the length of the semi-major axis is:

a = \sqrt{(12-0)^{2}+(0-0)^{2}}

a= 12

The length of the semi-minor axis is given by the following expression:

c =\sqrt{a^{2}-b^{2}}

b = \sqrt{a^{2}-c^{2}}

b = \sqrt{12^{2}-8^{2}}

b \approx 8.944

The equation of the ellipse is:

\frac{x^{2}}{144}+\frac{y^{2}}{79.995}=1

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