Let the number be Y .
Y is seven
less than 5 times another (let that other be X)
Y=7-5X
sum of both Y and X minus 4 gives one
Y+X-4=1
now solve both equations .
Let x = total sales of baked goods remember 20% = .20 as a decimal
so the equation would be .20x = $600
divide both sides by .20
.20x/.20 = $600/.20
x = $3000 the total sales of baked goods
CHECK: 20% times $3000 = .20 times $3000 = $600
Answer:
C
Step-by-step explanation:
Answer:
a= 5 and b=1
Step-by-step explanation:
To solve, we will follow the steps below:
2x + 3y = 7
(a-b)x + (a+b)y = 3a + b - 2
We should note that since it has infinitely many solutions then,

Hence
2/a-b = 3/a+b = 7/3a +b-2
2/a-b = 3/a+b
cross-multiply
3(a-b) = 2( a+b)
open the bracket
3a - 3b = 2a + 2b
collect like term
3a - 2a = 2b + 3b
a = 5b -------------------------------------------(1)
Similarly
3/a+b = 7/3a +b-2
cross-multiply
7(a+b) = 3(3a+b -2)
7a + 7b = 9a + 3b -6
take all the variables to the left-hand side of the equation
7a - 9a+ 7b-3b = -6
-2a + 4b = -6 ---------------------------------(2)
but a = 5b
substitute a= 5b in equation (2) and solve for b
-2(5) + 4b = -6
-10 + 4b = -6
add 10 to both-side of the equation
-10 + 10+ 4b = -6+10
4b = 4
divide both-side of the equation by 4
b = 1
substitute b= 1 in equation (1)
a = 5b
a =5(1)
a=5
Therefore, a= 5 and b=1
Answer:
Leslie has 13 quarters and 23 half-dollars.
Step-by-step explanation:
You can write the following equations from the information given and considering that a quarter is $0.25 and half-dollar is $0.50:
x+y=36 (1)
0.25x+0.50y=14.75 (2), where:
x=amount of quarters
y=amount of half-dollars
First, you can isolate x in (1):
x=36-y (3)
Then, you can replace (3) in (2):
0.25(36-y)+0.50y=14.75
9-0.25y+0.50y=14.75
0.25y=5.75
y=5.75/0.25
y=23
Finally, you can replace the value of y in (3) to find the value of x:
x=36-23
x=13
According to this, the answer is that Leslie has 13 quarters and 23 half-dollars.