Answer: 11
Step-by-step explanation:
Since the smaller triangle is half of the larger triangle
5.5×2=11
When the firecracker hits the ground, H(t) = 0.0 = -16t^2 + 90t + 160 Using the quadratic formula,t = (-90 +- sqrt(90^2 - 4(-16)(160))) / 2(-16)t = -1.42 ort = 7.04
The negative time is extraneous. Therefore,t = 7.04 s.
Seven Seconds is your answer!
24:15 would be the simplified version, if that's what you meant.
<u><em>The law illustrated is Distributive Law</em></u>
This question is under a topic called algebra laws.
The laws are;
- Commutative law; This implies that when we are to add or multiply numbers, the order of addition or multiplication doesn't matter as we will still get same result.
- Associative law; This implies that if we want to add more than 2 numbers, if we decide to add the first 2 before adding the third one, we will still get the same result as if we added the second one to the third one before adding to the first one. This law also applies to multiplication.
- Distributive law; This implies that when two numbers are multiplied to produce a result, both numbers are factors of the result.
We are told in the question that ; 5n x 1 = 5n
This means that 5n and 1 are factors of 5n and this corresponds to distributive law
Read more at; brainly.in/question/39479409?tbs_match=1
5) The relation between intensity and current appears linear for intensity of 300 or more (current = intensity/10). For intensity of 150, current is less than that linear relation would predict. This seems to support the notion that current will go to zero for zero intensity. Current might even be negative for zero intensity since the line through the points (300, 30) and (150, 10) will have a negative intercept (-10) when current is zero.
Usually, we expect no output from a power-translating device when there is no input, so we expect current = 0 when intensity = 0.
6) We have no reason to believe the linear relation will not continue to hold for values of intensity near those already shown. We expect the current to be 100 for in intensity of 1000.
8) Apparently, times were only measured for 1, 3, 6, 8, and 12 laps. The author of the graph did not want to extrapolate beyond the data collected--a reasonable choice.
