Answer:
C' (-4 , 2)
slope of new line = line "L" = -2
Step-by-step explanation:
C (x₀,y₀): (0,2) dilation center (h,k): (2,2) scale factor (sf): 3
C' (x,y)
x = 2 + 3*(0-2) = -4 x = h + sf*(x₀ - h)
y = 2 + 3*(2-2) = 2 y = k + sf*(y₀ - k)
5:2
40÷5=8
16÷2=8
hope this helps you!!
2
We have two points so we can find the slope
m = ( y2-y1)/(x2-x1)
= ( -11 - -1)/( 4 -9)
= (-11+1)/( 4-9)
-10/ -5
= 2
A) more people voted
I did it on edge