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4 years ago

How many real solutions does 4x^2+2x+5 = 0 have?

Mathematics

1 answer:

777dan777 [17]4 years ago

8 0

The answer is infinitely many

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Help please..<br><br> find the area of the region that lies inside both curves

just olya [345]

Too hard for me. I'm only in 5th grade

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3 years ago

Which triangles could not be similar to triangle ABC ? triangle a b c with right angle b. side a b is 12 cm. side b c is 5 cm. s

Vera_Pavlovna [14]

Answer:

triangle JKL

Step-by-step explanation:

This is because the lengths of each side JKL is a factor to ABC

respectively .

AB=12,JK=36

AC=13,JL=39

BC=5,KL=25

I hope you understand

6 0

2 years ago

Ayo helppp ill give u anthing

kicyunya [14]

Answer:

16.9 m

Step-by-step explanation:

Start with a half a circle. The central angle of a semicircle is 180 deg.

Now subtract 21 deg on each side.

180 - 21 - 21 = 138

The central angle is 138 deg.

The radius is 7 m.

Now we use the formula for the length of an arc of a circle given the radius of the circle and the central angle of the arc.

$s = \dfrac{n}{360^\circ}2 \pi r$

$s = \dfrac{138^\circ}{360^\circ}2(3.14159)(7~m)$

$s = 16.9~m$

4 0

3 years ago

What value of x makes the statement true?

Sergeu [11.5K]

Answer:

5x-1=10x+3x

5x-3x=10+1

2x=11

x=11/2

8 0

2 years ago

Read 2 more answers

Given that f.x 3x-2 over x+1 g[x] x +5 evaluate f[-4] and gf [-2]

Jobisdone [24]

The value of f[ -4 ] and g°f[-2] are $\frac{14}{3}$ and 13 respectively.

<h3>What is the value of f[-4] and g°f[-2]?</h3>

Given the function;

$f(x) = \frac{3x-2}{x+1}$
$g(x)=x+5$
f[ -4 ] = ?
g°f[ -2 ] = ?

For f[ -4 ], we substitute -4 for every variable x in the function.

$f(x) = \frac{3x-2}{x+1}\\\\f(-4) = \frac{3(-4)-2}{(-4)+1}\\\\f(-4) = \frac{-12-2}{-4+1}\\\\f(-4) = \frac{-14}{-3}\\\\f(-4) = \frac{14}{3}$

For g°f[-2]

g°f[-2] is expressed as g(f(-2))

$g(\frac{3x-2}{x+1}) = (\frac{3x-2}{x+1}) + 5\\\\g(\frac{3x-2}{x+1}) = \frac{3x-2}{x+1} + \frac{5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) = \frac{3x-2+5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) = \frac{8x+3}{x+1}\\\\We\ substitute \ in \ [-2] \\\\g(\frac{3x-2}{x+1}) = \frac{8(-2)+3}{(-2)+1}\\\\g(\frac{3x-2}{x+1}) = \frac{-16+3}{-2+1}\\\\g(\frac{3x-2}{x+1}) = \frac{-13}{-1}\\\\g(\frac{3x-2}{x+1}) = 13$

Therefore, the value of f[ -4 ] and g°f[-2] are $\frac{14}{3}$ and 13 respectively.

Learn more about composite functions here: brainly.com/question/20379727

#SPJ1

6 0

2 years ago