What is the solution set of the equation x ^ 2 - 3x - 10 = 0 ? pls show work

Mathematics

1 answer:

Yanka [14]3 years ago

7 0

Answer:

Factors :- (x - 5) (x + 2)

Values :- x = 5, x = -2

Step-by-step explanation:

= > x^2 - 3x - 10 = 0

= > x^2 - (5 - 2)x - 10 = 0

= > x^2 - 5x + 2x - 10 = 0

= > x (x - 5) + 2 (x - 5) = 0

= > (x + 2) ( x - 5) = 0...factors

= > x = 5, - 2...values

<h2>Hope it helps you!! </h2>

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<h3><u>Solution:</u></h3>

Given that, One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle.

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If they are parallel, sum of the described angles should be equal to 180 as they are same side exterior angles.

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$\begin{array}{l}{\rightarrow 1^{\text {st }} \text { angle }=\frac{1}{6} \times 90} \\\\ {\rightarrow 1^{\text {st }} \text { angle }=15 \text { degrees }}\end{array}$