Answer:
and
.
Step-by-step explanation:
So I believe the problem is this:

where we are asked to find values for
and
such that the equation holds for any
in the equation's domain.
So I'm actually going to get rid of any domain restrictions by multiplying both sides by (x-3)(x+7).
In other words this will clear the fractions.


As you can see there was some cancellation.
I'm going to plug in -7 for x because x+7 becomes 0 then.




Divide both sides by -10:


Now we have:
with 
I notice that x-3 is 0 when x=3. So I'm going to replace x with 3.




Divide both sides by 10:


So
and
.
9514 1404 393
Answer:
∠A = 44°
Step-by-step explanation:
In order to find the measure of angle A, you need to know the value of the variable x. This means you need some relation that you can solve to find x.
Happily, that relation is "the sum of angles in a triangle is 180°." This means ...
84° +(x +59)° +(x +51)° = 180°
(2x + 194)° = 180° . . . collect terms
2x = -14 . . . . . . . . . . divide by °, and subtract 194
x = -7 . . . . . . . . . . . .divide by 2
Now, the measure of angle A is ...
∠A = (x +51)° = (-7 +51)°
∠A = 44°
Answer:
D
Step-by-step explanation:
TAN is opposite/adjacent
15/8
We are given: Function y=f(x).
First x-intercept of the y=f(x) is 2.
x-intercept is a point on x-axis, where y=0.
Replacing y by 0 and x by 2 in above function, we get
0=f(2)
Second x-intercept of the y=f(x) is 3.
Replacing y by 0 and x by 2 in above function, we get
0=f(3)
We are given another function y=8f(x).
Here only function f(x) is being multiplied with 8.
That is y values of function should be multiply by 8.
Because we have y value equals 0. On multiplying 8 by 0 gives 0 again and it would not effect the values of x's.
Therefore,
x-intercepts of y=8f(x) would remain same, that is 2 and 3.
Answer: option 1.
Explanation:
feasible region is that region which is formed by the lines of constraints.
feasible region is shaded in the attached graph
inequalities becomes equalities to draw the graph
and lines will head towards the origin if constraint satisfied by putting x= 0, y=0
and on the contrary lines will move away from origin when condition of constraint does not satisfied.