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3 years ago

Which combination of solid and liquid would likely form a solution

Chemistry

1 answer:

Mademuasel [1]3 years ago

6 0

Answer:

lonic solid and polar liquid

Explanation:

Without more context I cannot fully answer, but upon researching your question I have found the answer of:

lonic solid and polar liquid

If this seems to work for you, great! If not please provide more context :))

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Using the periodic table, determine the number of PROTONS for the element Li<br>

KIM [24]

The number of protons for element Li is 3

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3 years ago

How many moles of magneslum chloride are there in 148 grams of magnesium chloride?

vodomira [7]

Answer:

1.554442238816872 moles

Explanation:

3 0

3 years ago

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Ammonia is formed according to the reaction below. A chemist mixes 21 grams of nitrogen gas and 18 grams of hydrogen gas in a 2.

Rama09 [41]

Answer : The mass of hydrogen gas consumed will be, 4.5 grams

Explanation : Given,

Mass of $N_2$ = 21 g

Mass of $H_2$ = 18 g

Molar mass of $N_2$ = 28 g/mole

Molar mass of $H_2$ = 2 g/mole

First we have to calculate the moles of $N_2$ and $H_2$ .

$\text{Moles of }N_2=\frac{\text{Mass of }N_2}{\text{Molar mass of }N_2}=\frac{21g}{28g/mole}=0.75moles$

$\text{Moles of }H_2=\frac{\text{Mass of }H_2}{\text{Molar mass of }H_2}=\frac{18g}{2g/mole}=9moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$N_2(g)+3H_2(g)\rightarrow 2NH_3(g)$

From the given balanced reaction, we conclude that

As, 1 mole of $N_2$ react with 3 moles of $H_2$

So, 0.75 moles of $N_2$ react with $3\times 0.75=2.25$ moles of $H_2$

From this we conclude that, $H_2$ is an excess reagent because the given moles are greater than the required moles and $N_2$ is a limiting reagent because it limits the formation of product.

The moles of hydrogen gas consumed = 2.25 mole

Now we have to calculate the mass of hydrogen gas consumed.

$\text{Mass of }H_2=\text{Moles of }H_2\times \text{Molar mass of }H_2$

$\text{Mass of }H_2=(2.25mole)\times (2g/mole)=4.5g$

Therefore, the mass of hydrogen gas consumed will be, 4.5 grams

5 0

4 years ago

Someone please help me

Setler79 [48]

Answer:

8510 mol

Explanation:you must divide both of the molar masses into each other

5 0

3 years ago

Five liters of air at -35°C is warmed to 89°C. What is the new volume if the pressure remains constant

Delicious77 [7]

Answer:

7.61 liters

Explanation:

From the question,

Applying Charles law formula,

V₁/T₁ = V₂/T₂...................... Equation 1

Where P₁ = initial volume of of air, V₂ = Final volume of air, T₁ = Initial Temperature of air, T₂ = Final Temperature of air.

make V₂ the subject of the equation

V₂ = (V₁×T₂)/T₁............... Equation 2

Given: V₁ = 5 liters, T₁ -35 °C = (-35+273) K = 238 K, T₂ = 89°C = (89+273) K = 362 K

Substitute these values into equation 2

V₂ = (5×362)238

V₂ = 1810/238

V₂ = 7.61 liters

8 0

3 years ago