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zheka24 [161]
2 years ago
6

Review

Chemistry
1 answer:
ZanzabumX [31]2 years ago
7 0

Answer:

1. Gold is valuable because of its high quality physical and chemical properties

2. The gold mines where the state's property in both Egyptian and Roman civilizations

3. The elixir of life is akin to the philosopher stone. It is a chemical portion that when drank, grants eternal life

4. The contribution of alchemists to modern chemistry, includes the formulation of the first ideological periodic table, the distillation process, metalworking, gunpowder, glass, ink, paints, cosmetics and many other innovations

Explanation:

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How much does a 130 kg object weigh on Earth?
Strike441 [17]

Answer:

1274

Explanation:

4 0
3 years ago
Read 2 more answers
How many moles of HNO3 are present in 450 g of HNO3?
iVinArrow [24]
Since there are 63.01284 grams to one mole of HNO3, then 12.5 moles would be in 450 grams of it.
6 0
2 years ago
The diameter of metal wire is often referred to by its American wire-gauge number. A 16 gauge-wire has a diameter of 0.05082 in.
lubasha [3.4K]

Answer:

length of wire = 38.82 m

Explanation:

∴ 16 gauge ≡ 0.05082 in * ( 2.54 cm/in ) = 0.12908 cm

∴ m spool = 1 Lb = 453.592 g

∴ ρ = 8.92 g/cm³

cross section area:

⇒ A = π*D²/4 = π*(0.12908)²/4 = 0.0131 cm²

⇒ L = ((453.592 g) *(cm³/8.92 g)) / ( 0.0131 cm² )

⇒ L = 3881.765 cm * ( m/100cm) = 38.82 m

8 0
3 years ago
matter is passed down from the living part of an ecosystem to the non living part when witch of the following take place ?
Ivenika [448]
I don’t know about that
7 0
2 years ago
You have come down with a nasty cold and would like to understand why the virus that infected you is making you feel so lousy. W
umka21 [38]

Answer:

a) The volume is 5.236x10⁻¹³L

b) The molarity of a single virus is 1.91x10¹² mol/L

c) The molarity for a 100 virus particles is 1.91x10¹⁴ mol/L

Explanation:

a) Given:

D = diameter of the cell = 10 μm

r = radius = 10/2 = 5 μm

The volume of the spherical cell is equal:

V=\frac{4}{3} \pi r^{3} =\frac{4}{3} \pi *(5)^{3} =523.6\mu m^{3}

If 1 μm³ = 1x10⁻¹⁵L, then 523.6 μm³ = 5.236x10⁻¹³L

b) The molarity is:

M=\frac{number-of-moles}{volume-of-solution}

For a single virus within the cell

M=\frac{1}{5.236x10^{-13} } =1.91x10^{12} mol/L

c) For a 100 virus particles the molarity is:

M=\frac{100}{5.236x10^{-13} } =1.91x10^{14} mol/L

4 0
3 years ago
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