Ask question

Ask question

All categories

Citrus2011 [14]

3 years ago

5

Mackenzie's company reimburses her $0.75 per mile that she drives for business. If she goes on a business trip and drives a tota

l of 982 miles, how much will her reimbursement be?

1 answer:

lesantik [10]3 years ago

6 0

Answer:90

Step-by-step explanation:

:)

You might be interested in

Please answer this question, will give brainliest!

Ad libitum [116K]

Answer:

I dont really know the answer.. but ill try; if its wrong I am so sorry;

Step-by-step explanation:

First you must get the area of a circle, which is; A= pi r squared

and all you have to do is fill it in like this;

A= 3.14 x 2.0

^

A= 6.28

5 0

3 years ago

Tom went bowling with $27 to spend.He rented shoes for $5.75 and paid $4.25 for each game.

RideAnS [48]

Answer:

5

Step-by-step explanation:

Subtract the spent money to rent cost:

27-5.75=21.25

Divide the answer to the cost of each game:

21.25/4.25=5

he played 5 times.

6 0

3 years ago

Allison has $35 to spend at the pet store. She buys a large dog bowl for $15 and dog shampoo for $8. She wants to buy some dog b

zysi [14]

Answer:

She can buy 9 bones.

Step-by-step explanation: Because 9 times 1.25 equals $11.25 for bones.

3 0

3 years ago

Equivalent ratios 78:100 to 39:50

Ne4ueva [31]

Well, they are equivalent, but I'm not sure if that's exactly what you're asking. :)

3 0

2 years ago

The mean yearly rainfall in Sydney, Australia, is about 134 mm and the standard deviation is about 66 mm ("Annual maximums of,"

svetlana [45]

Answer:

At least 202.44 mm in the top 15%.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 134, \sigma = 66$

How many yearly mm of rainfall would there be in the top 15%?

At least X mm.

X is the 100-15 = 85th percentile, which is X when Z has a pvalue of 0.85. So X when Z = 1.037.

$Z = \frac{X - \mu}{\sigma}$

$1.037 = \frac{X - 134}{66}$

$X - 134 = 66*1.037$

$X = 202.44$

At least 202.44 mm in the top 15%.

5 0

3 years ago