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3 years ago

The area of a circle is 113.10 what is the radius

Mathematics

1 answer:

Pie3 years ago

3 0

It’s be 1131/10 or 113.1

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Suppose that an object whose is 10th weighs 50 N find the weight of an object whose is 6 kg

Nady [450]

Weight is another term for the force from mass multiplied by acceleration due to gravity, the equation being expressed as $f = ma$ , being force, mass, and acceleration respectively.

We already have 2 parts of the equation, $50 = 10a$

Acceleration due to gravity on the planet is $5 m/s^2$

Plug it into the equation $f = ma$

$f=6kg$ x $5m/s^2$

Weight or force from gravity is 60N.

8 0

3 years ago

Can someone please give me the answer to these two?

Radda [10]

Answer:

3: D - Undefined

4: A - 1

Step-by-step explanation:

For Question 3 your answer is D, undefined, because it does not have a slope, a slope is like a hill, but that just goes straight up, thus it is undefined.

For Question 4 your answer is A, 1, because it moves one digit to the right and then 1 digit up, Thus that is your answer.

6 0

2 years ago

The given matrix is the augmented matrix for a linear system. Use technology to perform the row operations needed to transform t

shtirl [24]

Answer:

$x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\$

Step-by-step explanation:

As the given Augmented matrix is

$\left[\begin{array}{ccccc}9&-2&0&-4&:8\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]$

Step 1 :

$r_{1}$ ↔ $r_{1} - r_{2}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]$

Step 2 :

$r_{3}$ ↔ $r_{3} - 8r_{1}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\0&124&-54&77&:-82\end{array}\right]$

Step 3 :

$r_{2}$ ↔ $\frac{r_{2}}{7}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&124&-54&77&:-82\end{array}\right]$

Step 4 :

$r_{1}$ ↔ $r_{1} + 14r_{2}$ , $r_{3}$ ↔ $r_{3} - 124r_{2}$

$\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&- \frac{254}{7} &\frac{663}{7} &:-\frac{1690}{7} \end{array}\right]$

Step 5 :

$r_{3}$ ↔ $\frac{r_{3}. 7}{254}$

$\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&1&-\frac{663}{254} &:-\frac{1690}{254} \end{array}\right]$

Step 6 :

$r_{1}$ ↔ $r_{1} - 4r_{3}$ , $r_{2}$ ↔ $r_{2} + \frac{1}{7} r_{3}$

$\left[\begin{array}{ccccc}1&0&0&-\frac{71}{127} &:\frac{176}{127} \\0&1&0&-\frac{131}{254} &:\frac{284}{127} \\0&0&1&-\frac{663}{254} &:\frac{845}{127} \end{array}\right]$

∴ we get

$x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\$

6 0

2 years ago

What is 2/9 divided by 3?

Kryger [21]

((2÷9))÷3
(0.222)÷3
=0.074

3 0

3 years ago

Jamie rode her bike home for 5 blocks before realizing she forgot her math book at school and would need it for her homework. Sh

Alik [6]

B shows her getting closer to home, immediately turning round, gives time for finding book then riding all the way home at a constant speed

5 0

3 years ago

Read 2 more answers