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alisha [4.7K]
3 years ago
14

Patel is solving 8x2 + 16x + 3 = 0. Which steps could he use to solve the quadratic equation? Select three options.

Mathematics
1 answer:
Nataly [62]3 years ago
3 0
8(x2 + 2x + 1) = –3 + 8
x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot
x = –1 Plus or minus StartRoot StartFraction 4 Over 8 EndFraction EndRoot
8(x2 + 2x + 1) = 3 + 1
8(x2 + 2x) = –3
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inna [77]

Answer:

12 feet

Step-by-step explanation:

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4 years ago
0.25 ( 6g + 32 ) =<br> Show work please or explain :)
Lerok [7]

Answer:

0.25/6+32=32.0416666667

Step-by-step explanation:

I got this answer because i saw that the 0.25 was at the begining of the equation and i thought that was division and then the ones in perenthisis which was 6+32 and i got my answer buy using a calculater but i got the equation by my self.

4 0
3 years ago
The area of the parallelogram below is ____ square meters.
Gemiola [76]

Answer:

14 square meters

Step-by-step explanation:

The formula for the area of a parallelogram of length L and height H is

A  = L * H.

Here, the area is A = (2 meters) * (7 meters) = 14 square meters.

This answer hinged upon my understanding of this situation, and could be incorrect because I'm not taking into account the "triangle" mentioned here.  When at all possible you should share any diagrams given in the problem statement, or at least describe them accurately in words.

6 0
3 years ago
Read 2 more answers
JJill begins the summer with $500 in her savings account. Each week, she withdraws $20. Her brother, Sam,starts the summer with
meriva

Answer:

7th week

Step-by-step explanation:

Let us represent the number of weeks as x

Jill begins the summer with $500 in her savings account. Each week, she withdraws $20.

$500 - $20× x

500 - 20x

Her brother, Sam,starts the summer with $150 in his account. He adds $30 to his account each week.

$150 + $30 × x

150 + 30x

At what week will both Jill and Sam have the same amount in their account?

We solve this be Equating both Equations together

Jill = Sam

500 - 20x = 150 + 30x

Collect like terms

500 - 150 = 30x + 20x

350 = 50x

Divide both sides by 50

50x/50 = 350/50

x = 7 weeks

Therefore, at the 7 week, Jill and sam would have the same amount in their accounts

3 0
3 years ago
What is the solution to the linear equation? x – StartFraction 2 Over 3 EndFraction x minus StartFraction one-half EndFraction e
Anton [14]

<em>Your question is not well presented</em>

Question:

What is the solution to the linear equation?

x - \frac{2}{3}x - \frac{1}{2} = \frac{1}{3} + \frac{5}{6}x

Answer:

x = \frac{-5}{3}

Step-by-step explanation:

Given

x - \frac{2}{3}x - \frac{1}{2} = \frac{1}{3} + \frac{5}{6}x

Required

Simplify

x - \frac{2}{3}x - \frac{1}{2} = \frac{1}{3} + \frac{5}{6}x

Add \frac{1}{2} to both sides

x - \frac{2}{3}x - \frac{1}{2} + \frac{1}{2} = \frac{1}{3} + \frac{5}{6}x + \frac{1}{2}

x - \frac{2}{3}x = \frac{1}{3} + \frac{5}{6}x + \frac{1}{2}

Subtract \frac{5}{6}x from both sides

x - \frac{2}{3}x - \frac{5}{6}x= \frac{1}{3} + \frac{5}{6}x + \frac{1}{2} - \frac{5}{6}x

x - \frac{2}{3}x - \frac{5}{6}x= \frac{1}{3} + \frac{1}{2} + \frac{5}{6}x- \frac{5}{6}x

x - \frac{2}{3}x - \frac{5}{6}x= \frac{1}{3} + \frac{1}{2}

Take LCMs

\frac{6x - 4x -5x}{6}= \frac{2+3}{6}

\frac{-3x}{6}= \frac{5}{6}

Multiply both sides by 6

6 * \frac{-3x}{6}= \frac{5}{6} * 6

-3x= 5

Divide both sides by -3

\frac{-3x}{-3}= \frac{5}{-3}

x = \frac{5}{-3}

x = \frac{-5}{3}

5 0
4 years ago
Read 2 more answers
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