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Inga [223]
3 years ago
14

Which expression represents the sum of (2x-5y and (x+y) ?

Mathematics
1 answer:
gayaneshka [121]3 years ago
8 0
I have no clue you have to do something like x2-x1 over y1-y2 and you get yoyu answer from that. 
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Rewrite 1−2 sin ^2 (22.5∘) using a double-angle identity.
attashe74 [19]
Using the identity :

Cos (2a) = 1-2 Sin^2(a)

Therefore :<span>1−2 sin ^2 (22.5∘) = Cos(2a)
                                                = Cos (2 * 22.5) = Cos 45</span>
3 0
3 years ago
What is the difference of the fractions? Use the number line to help find the answer.
vova2212 [387]
<h2>Explanation:</h2>

Hello, remember you need to write complete questions in order to get good and exact answers. Here you haven't provided any fractions, so I'll give you my own fractions.

The first fraction is:

\frac{1}{2}

The second fraction is:

\frac{1}{4}

So let's say that difference is:

\frac{1}{2}-\frac{1}{4}

Therefore, the result is:

\frac{1}{2}-\frac{1}{4}=\frac{1}{4}

The representation of this problem is shown using the number line below. As you can see, we have written both 1/2 and 1/4 and the difference is also indicated giving the result 1/4. That is, if we walk from 1/4 to 1/2 we'll walk 1/4 units.

6 0
3 years ago
Read 2 more answers
NEED ASAP plz. I will also mark brainiest! Don't just take points, I will report you.
PilotLPTM [1.2K]

Part A:

You may choose the two lines connecting the origin and points A and B, and choose the portion of the space between them.

The line between the origin and A is

y = 3x

We want everything below this line (line included), so the first inequality is

y \leq 3x

The line between the origin and B is

y = \dfrac{1}{3}x

We want everything above this line (line included), so the second inequality is

y \geq \dfrac{1}{3}x

Create a system with these two inequalities and you'll have an area including only points A and B

Part B:

To verify the solutions, we can plug the coordinates of A and B in this system and check that we get something true: the coordinates of point A are (1,3), while the coordinates of point B are (3,1). The system becomes:

A:\begin{cases}3 \leq 3\cdot 1\\3 \geq \frac{1}{3}\cdot 1\end{cases},\quad B:\begin{cases}1 \leq 3\cdot 3\\1 \geq \frac{1}{3}\cdot 3\end{cases}

Which means

A:\begin{cases}3 \leq 3\\3 \geq \frac{1}{3}\end{cases},\quad B:\begin{cases}1 \leq 9\\1 \geq 1\end{cases}

And these are all true. So, the system is satisfied, which means that the points belong to the shaded area.

Part C

If you draw the line, you'll see that the only points that lay below the line are B and C. In fact, if we plug the coordinates we have

B:\ 1

And this are both true. You can check the coordinates of all other points, and see that they won't satisfy the inequality y<3x-6

3 0
3 years ago
Harley took out a 1-year loan for $2800 at an electronics store to be paid back
WARRIOR [948]

Answer:

2919.25

Step-by-step explanation:

I took a risk and answer on my test, and failed but here y'all go

5 0
3 years ago
Read 2 more answers
Which equation is true?
enot [183]
Lets solve all of these:-

#1

√361 = 361 · 2
         
         ?
√361 = 361 · 2
√361 = 19
361 · 2 = 722

19 ≠ 722
So this equation is not true

#2:-

√361 = 19²

         ?
√361 = 19²
√361= 19
19² = 19 · 19 = 361

19 ≠ 361
So this equation is not true

√361 = 361 ÷ 2 

         ?
√361 = 361 ÷ 2 
√361 = 19
361 ÷ 2 = 180.5

√361 ≠ 361 ÷ 2 
So this equation is not true

√361 = √19²
√361 = 19
√19² = 19

19 = 19

SO the last one is right. Hope I helped ya!! xD
4 0
3 years ago
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