106=x+x+5+x+8
106=3x+13
3x=93
x=31
(the sides are 31, 36, 39 respectively)
Answer:
The option A,D and E are correct.
Step-by-step explanation:
Given: 2x^3-250x^2
Factor : 2x^2(x-125)
So, GCF = 2x^2
Now a = 1 and b= 5
we know that a^3-b^3 = (a-b)(a^2+ab+b^2)
(x)^3 - (5)^3 = (x-5)(x^2+5x+25)
So, the option A,D and E are correct.
Six. 2 1/3=7/3-> to get to have a denominator of 6 multiply by 2 to get 14/6
Then 1/2=3/6
14/6 + 3/6 = 17/6
17/6= 2 5/6
First, find the slope (m) =
=
=
= 
Now plug in ONE of the points and the slope into the point-slope equation:
y - y₁ = m(x - x₁); where (x₁, y₁) is the chosen point.
y - 5 =
(x - 1) (I used (1,5) as the chosen point)
3(y - 5) = x - 1
3y - 15 = x - 1
3y -14 = x
-14 = x - 3y → x - 3y = -14
Answer: x - 3y = -14
Your inequality looks like this:

To get rid of the /6, you need to multiply by 6 as the opposite operation cancels it out. So, all you need to do is multiply both sides by 6 to isolate x.
Therefore: