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3 years ago

Four students were discussing how to find the unit rate for a proportional relationship.Which method is valid?

Mathematics

1 answer:

jenyasd209 [6]3 years ago

6 0

Answer:use a calculator

Step-by-step explanation:

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a A gallery is using glass display cases to display artifacts. They need to cover each display case with a sheet of clear protec

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Answer:

3x)^3=3^3*x^3=27x^3

Step-by-step explanation:

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2 years ago

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Multiply 400 and 45.2 together. <br> Round to the nearest hundredth when necessary. <br> Answer:

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Answer:

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Step-by-step explanation:

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3 years ago

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I can’t figure it out, it’s the same problem it just printed out twice

aleksklad [387]

Answer:

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Step-by-step explanation:

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3 years ago

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A classmate simplified a rational expression below

lara31 [8.8K]

<h2>Part a) </h2><h2>Explain the error in this simplification.</h2>

Given the simplified expression

$1-\frac{2}{x-2}=\frac{x+1}{x+2}$

$1-2\left(x+2\right)=\left(x+1\right)\left(x-2\right)$

$\:1-2x-4=x^2-x-2$

$-2x-3=x^2-x-2\:\:$

$0=x^2-2x-2\:\:$

$0=\left(x-1\right)\left(x-1\right)$

$x=1$

<u><em>Identifying the Main Error</em></u>

$1-\frac{2}{x-2}=\frac{x+1}{x+2}$

$1-2\left(x+2\right)=\left(x+1\right)\left(x-2\right)$ ← ERROR Starts here

<u><em>Here is the Explanation of the Error </em></u>

<u><em /></u> $\mathrm{The\:equation\:should\:have\:been\:Multiplied\:by\:LCM=}\left(x-2\right)\left(x+2\right)$ <em>. </em>In your case you wrongly multiply the equation.

<em><u>CORRECTION</u></em>

<em>HERE IS HOW YOU SHOULD HAVE MULTIPLIED BY </em><em>LCM = (x-2)(x+2):</em>

<em />

$1-\frac{2}{x-2}=\frac{x+1}{x+2}$

$1\cdot \left(x-2\right)\left(x+2\right)-\frac{2}{x-2}\left(x-2\right)\left(x+2\right)=\frac{x+1}{x+2}\left(x-2\right)\left(x+2\right)$

$\left(x-2\right)\left(x+2\right)-2\left(x+2\right)=\left(x+1\right)\left(x-2\right)$

<h2>Part b) </h2><h2>Show your work as you correct the error</h2>

Here is the complete correction of the error.

Considering the expression

$1-\frac{2}{x-2}=\frac{x+1}{x+2}$

$\mathrm{Find\:Least\:Common\:Multiplier\:of\:}x-2,\:x+2:\quad \left(x-2\right)\left(x+2\right)$

$1\cdot \left(x-2\right)\left(x+2\right)-\frac{2}{x-2}\left(x-2\right)\left(x+2\right)=\frac{x+1}{x+2}\left(x-2\right)\left(x+2\right)$

$\left(x-2\right)\left(x+2\right)-2\left(x+2\right)=\left(x+1\right)\left(x-2\right)$

$x^2-2x-8=x^2-x-2$

$x^2-2x-8+8=x^2-x-2+8$

$x^2-2x=x^2-x+6$

$-x=6$

$\frac{-x}{-1}=\frac{6}{-1}$

$x=-6$

3 0

3 years ago

Need help with # 12 for distance/ midpoints formula. And another problem for #1 distance, segment and radicals ? Please help

Alenkinab [10]

Step-by-step explanation:

#12

PQ = 6x + 25

QR = 16 - 3x

PR = 6x + 25 + 16 - 3x

PR = 3x + 41

D = √(-4 - 5)² + (-7 - 2)²

D = √(-9)² + (-9)²

D = √81 + 81

D = √162

D = 9√2

3 0

3 years ago