Question

Graph the system of equations 4x+4y=16 x+6y=-6

Answer 1

Answer:

Graph has been shown in the attached file.

Step-by-step explanation:

We have been given the system of equations

$4x+4y=16.......(1)\\x+6y=-6.........(2)$

Both the equation represents a straight lines. We can find the x and y intercepts of these lines to graph.

The intercept form of a line is given by

$\frac{x}{a}+\frac{y}{b}=1$

Here a is the x - intercept and b is the y-intercept.

Divide both sides of the equation (1) by 16

$\frac{4x}{16}+\frac{4y}{16}=1\\\\\frac{x}{4}+\frac{y}{4}=1$

Hence, x-intercept = 4 and the point is (4,0)

y-intercept = 4 and the point is (0,4)

Similarly, for the second line

Divide both sides of the equation (2) by -6

$\frac{x}{-6}+\frac{6y}{-6}=1\\\\\frac{x}{-6}+\frac{y}{-1}=1$

x-intercept = -6 and the point is (-6,0)

y-intercept = -1 and the point is (0,-1)

We'll plot these points in the xy- plane and then join to get the graph of these lines.